In the problem shown in the picture it is already solvedDetermine the design strength of an ASTM A992 W14 x 132 that is part of a braced frame. Assume that the physical length L = 30 ft., the ends are pinned and the 18 column is braced at the ends only for the X-X axis and braced at the ends and mid-height for the Y-Y axis.The question isWhy is Sample Problem #4 a non-slender member? Is it desirable? Why? SAMPLE PROBLEM #4 Determine the design strength of an ASTM A992 W14 x 132 that ispart of a braced frame. Assume that the physical length L = 30 ft., the ends are pinned and the17column is braced at the ends only for the X-X axis and braced at the ends and mid-height for theY-Y axis.Solution• Step I. Calculate the effective lengths.For W14 x 132:Ix = 6.28 in;ry = 3.76 in; Ag =38.8 in?Kx = 1.0andKy = 1.0Lx = 30 ft. andLy = 15 ft.K,Lx = 30 ft. and K,Ly = 15 ft.• Step II. Determine the governing slenderness ratioKL/rx = 30 x 12 in./6.28 in.= 57.32KyLy/ry = 15 x 12 in./3.76 in. = 47.87The larger slenderness ratio, therefore, buckling about the major axis will govern the columnstrength.• Step III. Calculate the column strengthK,L,30= 17,96 ft.Therefore, (KL)eq =r, /r,KLx = 30 ft.6.28/3.76From Table 4-1,for (KL)eq = 18.0 ft. Ø.Pn = 1370 kips (design column strength)• Step IV. Check the local buckling limitsEFor the flanges, br/2tr = 7.14Ar = 0.56 x= 13.5F,= 35.9VF,For the web, h/tw = 15.5d = 1.49 xTherefore, the section is nonslender. OK.

The given data is shown below: W14×132L=30 ft

Answered: In the problem shown in the picture it…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

In the problem shown in the picture it is already solved Determine the design strength of an ASTM A992 W14 x 132 that is part of a braced frame. Assume that the physical length L = 30 ft., the ends are pinned and the 18 column is braced at the ends only for the X-X axis and braced at the ends and mid-height for the Y-Y axis. The question is Why is Sample Problem #4 a non-slender member? Is it desirable? Why?

SAMPLE PROBLEM #4 Determine the design strength of an ASTM A992 W14 x 132 that is
part of a braced frame. Assume that the physical length L = 30 ft., the ends are pinned and the
17
column is braced at the ends only for the X-X axis and braced at the ends and mid-height for the
Y-Y axis.
Solution
• Step I. Calculate the effective lengths.
For W14 x 132:
Ix = 6.28 in;
ry = 3.76 in; Ag =38.8 in?
Kx = 1.0
and
Ky = 1.0
Lx = 30 ft. and
Ly = 15 ft.
K,Lx = 30 ft. and K,Ly = 15 ft.
• Step II. Determine the governing slenderness ratio
KL/rx = 30 x 12 in./6.28 in.= 57.32
KyLy/ry = 15 x 12 in./3.76 in. = 47.87
The larger slenderness ratio, therefore, buckling about the major axis will govern the column
strength.
• Step III. Calculate the column strength
K,L,
30
= 17,96 ft.
Therefore, (KL)eq =
r, /r,
KLx = 30 ft.
6.28/3.76
From Table 4-1,
for (KL)eq = 18.0 ft. Ø.Pn = 1370 kips (design column strength)
• Step IV. Check the local buckling limits
E
For the flanges, br/2tr = 7.14
Ar = 0.56 x
= 13.5
F,
= 35.9
VF,
For the web, h/tw = 15.5
d = 1.49 x
Therefore, the section is nonslender. OK.

Expert Solution

Step by step

Solved in 6 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions