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In the previous step we determined the piecewise continuous function f(t). So, f(t) = |2t – 2, 0 1 We now use this to find the Laplace transform L{f(t)} e-stret) dt. Since f is defined in two pieces, L{(t)} is expressed as the sum of two integrals. L{f(t)} -strce) dt 00 dt + 2t - dt = 0 + (t – 1)e-st dt

In the previous step we determined the piecewise continuous function f(t). So, f(t) = |2t – 2, 0 1 We now use this to find the Laplace transform L{f(t)} e-stret) dt. Since f is defined in two pieces, L{(t)} is expressed as the sum of two integrals. L{f(t)} -strce) dt 00 dt + 2t - dt = 0 + (t – 1)e-st dt

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In the previous step we determined the piecewise continuous function f(t). f(t) = 2t So, 0 <ts 1 t > 1 2, We now use this to find the Laplace transform L{f{t)} = -strt) dt. Since f is defined in two pieces, e L{f(t)} is expressed as the sum of two integrals. L{r(t)} e-st(t) dt dt + dt = 0 + (t - 1)e-st dt
Transcribed Image Text:In the previous step we determined the piecewise continuous function f(t). f(t) = 2t So, 0 <ts 1 t > 1 2, We now use this to find the Laplace transform L{f{t)} = -strt) dt. Since f is defined in two pieces, e L{f(t)} is expressed as the sum of two integrals. L{r(t)} e-st(t) dt dt + dt = 0 + (t - 1)e-st dt
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