In the presence of CN, Fe+ forms the complex ion Fe(CN),*. The equilibrium concentrations of Fe+ and Fe(CN),* are 8.5 x 10-40 M and 1.6 x 10-3 M, respectively, in a 0.10-M KCN solution. Calculate the value for the overall formation constant of Fe(CN),*. Fe* (aq) + 6CN¯ (aq) = Fe(CN),*(aq) Koverall

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Chapter1: Chemical Foundations
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In the presence of
CN,
Fe+ forms the complex ion
Fe(CN),*. The equilibrium concentrations of
Fe+ and
Fe(CN),* are
8.5 x 10-40 M and
1.6 x 10-3 M, respectively, in a 0.10-M
KCN solution. Calculate the value for the overall formation constant of
Fe(CN),*.
Fe* (aq) + 6CN¯ (aq) = Fe(CN),*(aq)
Koverall
Transcribed Image Text:In the presence of CN, Fe+ forms the complex ion Fe(CN),*. The equilibrium concentrations of Fe+ and Fe(CN),* are 8.5 x 10-40 M and 1.6 x 10-3 M, respectively, in a 0.10-M KCN solution. Calculate the value for the overall formation constant of Fe(CN),*. Fe* (aq) + 6CN¯ (aq) = Fe(CN),*(aq) Koverall
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