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In the position shown, bar AB has a constant angular velocity of o rad/s counterclockwise. The values of the parameters are given in the table. Take counter-clockwise rotation to be positive. Complete the table by filling in the values in the yellow cells. A 100 mm B OAB 225 mm 75mm Table 2 L (mm) oAB (rad/s) BD (rad/s)@pE (rad/s) 300

In the position shown, bar AB has a constant angular velocity of o rad/s counterclockwise. The values of the parameters are given in the table. Take counter-clockwise rotation to be positive. Complete the table by filling in the values in the yellow cells. A 100 mm B OAB 225 mm 75mm Table 2 L (mm) oAB (rad/s) BD (rad/s)@pE (rad/s) 300

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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hello, this two question are different question but making use of the same techniques, however i am unable to get the answer for the yellow boxes after applying the steps in the solutions. can you help me do a step by step using the same method in the solution for the yellow boxes

Q2. In the position shown, bar AB has a constant angular velocity of o rad/s counterclockwise. The values of the parameters are given in the table. Take counter-clockwise rotation to be positive. Complete the table by filling in the values in the yellow cells. 100 mm B OAR E D 225 mm 75mm Table 2 |L (mm)/@ дв (rаd/s) Bр (rad/s)(aDE (rad/s) 300
Transcribed Image Text:Q2. In the position shown, bar AB has a constant angular velocity of o rad/s counterclockwise. The values of the parameters are given in the table. Take counter-clockwise rotation to be positive. Complete the table by filling in the values in the yellow cells. 100 mm B OAR E D 225 mm 75mm Table 2 |L (mm)/@ дв (rаd/s) Bр (rad/s)(aDE (rad/s) 300
1. Collar A moves in a constant velocity of 900 mm/s to the right. At the instant when 0 = 30°, determine (a) the angular velocity of rod AB, (b) the velocity of collar B. (BJ 15.34 on page 721) 30° 70° B Solution A With O-xy, we can express 30° 70° v, = 90020° = 900 î (mm/s) A B TRA = 300Z- 30° = 300 (0.866 î – 0.5 ĵ) (mm) Vg = VgZ-70° = V½( 0.342î – 0.94 Ĵ) (mm/s) Using v, V, + öx ĩ gives BA A V ( 0.342 î – 0.94 ĵ) = 900 î + Ôk × 300 (0.866 î – 0.5 ĵ) | "АВ" Component of î: 0.342 vB Ov A 150 0 = 900 (1) ליק Component of ĵ: VB A 0.94 v B + 259.80 = 0 (2) Solving the simultaneous equations (1) and (2) gives B VB = 1017 (mm/s) 3.68 (rad/s) Hence v = 1017Z-70° (mm/s) (ans) ö = ék= - 3.68 k (ans)
Transcribed Image Text:1. Collar A moves in a constant velocity of 900 mm/s to the right. At the instant when 0 = 30°, determine (a) the angular velocity of rod AB, (b) the velocity of collar B. (BJ 15.34 on page 721) 30° 70° B Solution A With O-xy, we can express 30° 70° v, = 90020° = 900 î (mm/s) A B TRA = 300Z- 30° = 300 (0.866 î – 0.5 ĵ) (mm) Vg = VgZ-70° = V½( 0.342î – 0.94 Ĵ) (mm/s) Using v, V, + öx ĩ gives BA A V ( 0.342 î – 0.94 ĵ) = 900 î + Ôk × 300 (0.866 î – 0.5 ĵ) | "АВ" Component of î: 0.342 vB Ov A 150 0 = 900 (1) ליק Component of ĵ: VB A 0.94 v B + 259.80 = 0 (2) Solving the simultaneous equations (1) and (2) gives B VB = 1017 (mm/s) 3.68 (rad/s) Hence v = 1017Z-70° (mm/s) (ans) ö = ék= - 3.68 k (ans)
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