In the planning stage, a sample proportion is estimated as pˆp^ = 48/80 = 0.60. Use this information to compute the minimum sample size n required to estimate p with 99% confidence if the desired margin of error E = 0.16. What happens to n if you decide to estimate p with 95% confidence? (You may find it useful to reference the z table. Round up final answers to nearest whole number.)

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