In the photoelectric effect experiment, the number of the emitted electrons increases by
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Q: The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic…
A: Photoelectric cut-off voltage, Vo = 1.5 V
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Q: The work function for lead is 4.14 eV. (a) Find the cutoff wavelength for lead. nm (b) What is the…
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Q: Determine the wavelength of a 2.5 keV electron.
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Q: the cutoff wavelength for a particular material is 510nm considering the photoelectric effect, what…
A: L0=510 nmL=402 nm let kinetic energy be K formula for K=> K=hcL-hcL0
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Q: 140-keV gamma ray has a photoelectric interaction with a K-shell electron of lead (Eß=88 keV). What…
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Q: In the photoelectric effect a photon hits a metal surface and ejects an electron. The energy of the…
A: Answer :- (C)
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- Ultraviolet radiation of wavelength 121 nm is used to irradiate a sample of potassium metal. The work function of potassium is 2.25 eV. Calculate the speed of the electrons emitted through the photoelectric effect.Photoelectrons with a maximum kinetic energy of 7.95 eV are emitted from a metal when it is illuminated by ultraviolet radiation with a wavelength of 1.25 × 10-7 m. (i) Calculate the energy of the incident photons in electronvolts. (ii) Calculate the wavelength of the radiation (in nanometres) corresponding to the lowest energy photons that can free electrons from the metal. (iii) How do you explain the fact that, when infrared radiation is shone on this metal, no photoelectrons are emitted?In the photoelectric effect, the work function increases if more electrons are emitted. depends only on the metal used. depends on how many photons hit. depends on the frequency of the incident photons. is always larger than the kinetic energy of the emitted electrons.
- If the cutoff wavelength for a particular material is 676 nm considering the photoelectric effect, what will be the maximum amount of kinetic energy obtained by a liberated electron when light with a wavelength of 403 nm is used on the material? Express your answer in electron volts (eV).42 If frequency of light used in photoelectric effect is 4.5x10 ^14 Hz and K.E of ejected electrons is 1.20 e V then work function of the metal will be * 6.6 e V 1.90 e V 0.66 e V O 2.54 e Vs) The cutoff frequency of a specific metal is known to be 0.72x1015Hz. During a photoelectric experiment, 3.7x102º photons with a wavelength of 167nm are striking a plate every second. What is the power of the photons and what is the maximum kinetic energy of the ejected electrons?