In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=7++R and an adjacent C-H bond is at the direction B-7--R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 1.03j + 0.82k B=0.85i + -0.82j + -1.01k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=7++R and an adjacent C-H bond is at the direction B-7--R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 1.03j + 0.82k B=0.85i + -0.82j + -1.01k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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![QUESTION 5
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction
of
A=î++R
and an adjacent C-H bond is at the direction
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a
new spectroscopy analysis, the adjacent bond vectors was found to be
A= 0.931 + 103] + 0.82k
B 0.851 + -0.82j + -1.01k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
QUESTION 6
Supply what is asked with the correct integer values, i.e. no decimal places. Do not forget the negative sign (-) if needed.
The position vs. time graph of a moving particle for a time interval of 23 seconds is shown below. Each square unit in the horizontal axis corresponds to one second,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af6d02a-3fd9-4aca-804f-1e98c8b1c79e%2F173ef0f6-7d61-41f6-87d1-b7a64c814516%2F4vfznc7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 5
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction
of
A=î++R
and an adjacent C-H bond is at the direction
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a
new spectroscopy analysis, the adjacent bond vectors was found to be
A= 0.931 + 103] + 0.82k
B 0.851 + -0.82j + -1.01k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
QUESTION 6
Supply what is asked with the correct integer values, i.e. no decimal places. Do not forget the negative sign (-) if needed.
The position vs. time graph of a moving particle for a time interval of 23 seconds is shown below. Each square unit in the horizontal axis corresponds to one second,
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