In the LCS problem, we are given as input two sequences, X = (r1, x2,….., Im) and Y = (y1,y2, ..., Yn) and would like to find a longest subsequence common to both. Towards this end, we define c[i, j] := length of LCS of X; and Yj, where X; := (r1,82, ...2?) and Y; := (y1, 42, ..y;) and obtain the following recurrence. if i = 0 or j = 0 if i, j > 0 and r; = Yj | max(c[i, j – 1], c[i – 1, j) if i,j > 0 and xi + Yj c[i, j] = { c[i – 1, j – 1) +1 Analyze the (asymptotic) running time: What is the running time for computing the optimum?

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In the LCS problem, we are given as input two sequences, X = (r1, r2, ..., Im)
and Y = (y1, y2, ..., Yn) and would like to find a longest subsequence common to both.
Towards this end, we define c[i, j] := length of LCS of X; and Y;, where X; := (x1, 2, ...;)
and Y; := (y1, y2, -.y;) and obtain the following recurrence.
if i = 0 or j = 0
if i, j > 0 and ri = Yj
if i, j > 0 and r; # Yj
c[i, j] = { c[i – 1, j – 1] +1
max(c[i, j – 1], c[i – 1,j])
Analyze the (asymptotic) running time:
What is the running time for computing the optimum?
Transcribed Image Text:In the LCS problem, we are given as input two sequences, X = (r1, r2, ..., Im) and Y = (y1, y2, ..., Yn) and would like to find a longest subsequence common to both. Towards this end, we define c[i, j] := length of LCS of X; and Y;, where X; := (x1, 2, ...;) and Y; := (y1, y2, -.y;) and obtain the following recurrence. if i = 0 or j = 0 if i, j > 0 and ri = Yj if i, j > 0 and r; # Yj c[i, j] = { c[i – 1, j – 1] +1 max(c[i, j – 1], c[i – 1,j]) Analyze the (asymptotic) running time: What is the running time for computing the optimum?
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