**Question 2:**In the lab, you have a beaker containing 40.0 mL of 0.50 M HNO₂. If you add 20.0 mL of 1.0 M CsOH, what will the pH and pOH be?**Explanation:**This question involves an acid-base reaction. You are given a volume and concentration of a weak acid (HNO₂) and a strong base (CsOH) and are tasked with calculating the resulting pH and pOH after the base is added.1. **Determine moles of each reactant:** - Moles of HNO₂ = 0.040 L × 0.50 mol/L = 0.020 moles - Moles of CsOH = 0.020 L × 1.0 mol/L = 0.020 moles2. **Reaction:** - Since CsOH is a strong base, it will react completely with HNO₂, a weak acid. - The equation for the reaction: HNO₂ + CsOH → CsNO₂ + H₂O3. **Determine the remaining moles:** - Since moles of HNO₂ = moles of CsOH, they will completely neutralize each other: - Remaining moles of HNO₂ = 0 - Remaining moles of CsOH = 04. **Resulting solution:** - Since both reactants are used, the resulting solution is neutral.5. **Calculate the pH and pOH:** - A neutral solution at 25°C has a pH of 7 and a pOH of 7.The problem demonstrates how to compute the pH and pOH after a neutralization reaction between a weak acid and a strong base.

HNO2 (nitrous acid) is weak acid and it's Ka value is 4.5 × 10-4 CsOH is a strong base. Equal…

Answered: In the lab, you have a beaker…

In the lab, you have a beaker containing 40.0 mL of 0.50 M HNO2. If you add 20.0 mL of 1.0 M CSOH, what will the pH and pOH be?

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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