In the KamLAND experiment, antineutrinos are detected via the reaction ve +p→ e+ +n, where the target protons are at rest. Show that for incident antineutrinos of energy E, = 3 MeV, the positron produced has an energy E+ = E, + mp – mn = 1.71 MeV (2.49) |
In the KamLAND experiment, antineutrinos are detected via the reaction ve +p→ e+ +n, where the target protons are at rest. Show that for incident antineutrinos of energy E, = 3 MeV, the positron produced has an energy E+ = E, + mp – mn = 1.71 MeV (2.49) |
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H5.
Transcribed Image Text:In the KamLAND experiment, antineutrinos are detected via the
reaction De +p → e+ +n, where the target protons are at rest. Show
that for incident antineutrinos of energy E, = 3 MeV, the positron
produced has an energy
2.7
E+
Ev + mp
- mn = 1.71 MeV
(2.49)
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