In the hydraulic jack shown, a force of 100 N is exerted on the small piston. Determine the upward force on the large piston. The area of the small piston is 65 cm2, and the area of the large piston is 950 cm2. If the small piston moves 12 cm, how far will the large move? Assume the oil to be incompressible.

Elements Of Electromagnetics
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In the hydraulic jack shown, a force of 100 N is exerted on the small piston. Determine the upward force on the large piston. The area of the small piston is 65 cm2, and the area of the large piston is 950 cm2. If the small piston moves 12 cm, how far will the large move? Assume the oil to be incompressible.

This diagram illustrates a basic hydraulic system composed of a small piston and a large piston, both of which are immersed in oil. 

- The small piston is labeled with an applied force of 100 N (Newtons).
- The large piston has an unknown force labeled as \(F = ?\).

The diagram depicts the principles of Pascal's Law, which states that pressure exerted on a confined fluid is transmitted undiminished in all directions throughout the fluid. Here, the pressure applied to the small piston is transmitted through the oil to the large piston.

To further analyze:

1. **Small Piston**: The force of 100 N is applied downwards onto the small piston.
2. **Large Piston**: The large piston is experiencing an upward force, which is to be determined (\(F = ?\)).

Given that the area of the large piston is greater than that of the small piston, the force exerted by the large piston will be proportionally larger due to the larger area, in accordance with the equation of hydraulic systems:

\[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \]

where:
- \(F_1\) is the force on the small piston (100 N)
- \(A_1\) is the area of the small piston
- \(F_2\) is the force on the large piston (unknown)
- \(A_2\) is the area of the large piston

By rearranging the equation to solve for \(F_2\) (force on the large piston), one can determine the unknown force exerted by the large piston:

\[ F_2 = F_1 \times \frac{A_2}{A_1} \]
Transcribed Image Text:This diagram illustrates a basic hydraulic system composed of a small piston and a large piston, both of which are immersed in oil. - The small piston is labeled with an applied force of 100 N (Newtons). - The large piston has an unknown force labeled as \(F = ?\). The diagram depicts the principles of Pascal's Law, which states that pressure exerted on a confined fluid is transmitted undiminished in all directions throughout the fluid. Here, the pressure applied to the small piston is transmitted through the oil to the large piston. To further analyze: 1. **Small Piston**: The force of 100 N is applied downwards onto the small piston. 2. **Large Piston**: The large piston is experiencing an upward force, which is to be determined (\(F = ?\)). Given that the area of the large piston is greater than that of the small piston, the force exerted by the large piston will be proportionally larger due to the larger area, in accordance with the equation of hydraulic systems: \[ \frac{F_1}{A_1} = \frac{F_2}{A_2} \] where: - \(F_1\) is the force on the small piston (100 N) - \(A_1\) is the area of the small piston - \(F_2\) is the force on the large piston (unknown) - \(A_2\) is the area of the large piston By rearranging the equation to solve for \(F_2\) (force on the large piston), one can determine the unknown force exerted by the large piston: \[ F_2 = F_1 \times \frac{A_2}{A_1} \]
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