Consider the equation: e0.4x + x³ = cos(x + 1) 1 Approximate the root in the interval [-0.373,-0.3725] with accuracy 10-6, using Bisection method. 2. Approximate the root with accuracy 10-6, using Newton method. (Set x = -1). 3. Approximate the root with accurach 10-6,using Secant method. (Set Xo = -1, x₁ = -0.5).

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Consider the equation:
e0.4x + x³ = cos(x + 1)
1 Approximate the root in the interval [-0.373,-0.3725] with accuracy 10-6, using Bisection method.
2. Approximate the root with accuracy 10-6, using Newton method. (Set x = -1).
3. Approximate the root with accurach 10-6,using Secant method. (Set Xo = -1, x₁ = -0.5).
Transcribed Image Text:Consider the equation: e0.4x + x³ = cos(x + 1) 1 Approximate the root in the interval [-0.373,-0.3725] with accuracy 10-6, using Bisection method. 2. Approximate the root with accuracy 10-6, using Newton method. (Set x = -1). 3. Approximate the root with accurach 10-6,using Secant method. (Set Xo = -1, x₁ = -0.5).
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