In the given problem, we implicitly differentiate by taking the derivative with respect to x of both sides of the equation. 응0=(5 cos(x + y)) Evaluate the derivative with respect to x of the left-hand side of the equation, y. dy dx dx

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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In the given problem, we implicitly differentiate by taking the derivative with respect to \( x \) of both sides of the equation.

\[
\frac{d}{dx}(y) = \frac{d}{dx}\left(5 \cos(x + y)\right)
\]

Evaluate the derivative with respect to \( x \) of the left-hand side of the equation, \( y \).

\[
\frac{d}{dx}(y) = \left(\square\right) \frac{dy}{dx}
\]
Transcribed Image Text:In the given problem, we implicitly differentiate by taking the derivative with respect to \( x \) of both sides of the equation. \[ \frac{d}{dx}(y) = \frac{d}{dx}\left(5 \cos(x + y)\right) \] Evaluate the derivative with respect to \( x \) of the left-hand side of the equation, \( y \). \[ \frac{d}{dx}(y) = \left(\square\right) \frac{dy}{dx} \]
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ddx(y)=ddx(5cos(x+y))

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