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In the game of roulette, a player can place a $8 bet on the number 6 and have a probability of winning. If the metal ball lands on 6, the player gets to keep the $8 paid to play the game and the player is awarded an additional $280. Otherwise, 38 the player is awarded nothing and the casino takes the player's $8. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $. (Round to the nearest cent as needed.)

In the game of roulette, a player can place a $8 bet on the number 6 and have a probability of winning. If the metal ball lands on 6, the player gets to keep the $8 paid to play the game and the player is awarded an additional $280. Otherwise, 38 the player is awarded nothing and the casino takes the player's $8. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $. (Round to the nearest cent as needed.)

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section: Chapter Questions
Problem 41CT: On a game show, a contestant is given the digits 3, 4, and 5 to arrange in the proper order to form...
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1 In the game of roulette, a player can place a $8 bet on the number 6 and have a probability of winning. If the metal ball lands on 6, the player gets to keep the $8 paid to play the game and the player is awarded an additional $280. Otherwise, 38 the player is awarded nothing and the casino takes the player's $8. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $ (Round to the nearest cent as needed.)
Transcribed Image Text:1 In the game of roulette, a player can place a $8 bet on the number 6 and have a probability of winning. If the metal ball lands on 6, the player gets to keep the $8 paid to play the game and the player is awarded an additional $280. Otherwise, 38 the player is awarded nothing and the casino takes the player's $8. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $ (Round to the nearest cent as needed.)
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