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In the form y - y₁=m(x-x₁), find the equation of the line that is the perpendicular- bisector of the line segment that joins (0,0) and (2a,2b). Select one: a. y-2b =(x-2a) b. y-a=(x-b) O c. y-b=(x-a) O d. y-b=(x-a)

In the form y - y₁=m(x-x₁), find the equation of the line that is the perpendicular- bisector of the line segment that joins (0,0) and (2a,2b). Select one: a. y-2b =(x-2a) b. y-a=(x-b) O c. y-b=(x-a) O d. y-b=(x-a)

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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In the form y - y₁=m(x − x₁), find the equation of the line that is the perpendicular- bisector of the line segment that joins (0,0) and (2a,2b). Select one: a. y-2b =(x-2a) b. y-a=(x-b) c. y-b= -(x-a) O d. y-b=(x-a)
Transcribed Image Text:In the form y - y₁=m(x − x₁), find the equation of the line that is the perpendicular- bisector of the line segment that joins (0,0) and (2a,2b). Select one: a. y-2b =(x-2a) b. y-a=(x-b) c. y-b= -(x-a) O d. y-b=(x-a)
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