In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC. D E Below is the proof that DE = CB. The proof is divided into four parts, where the title of each part indicates its main purpose. Complete part D of the proof. DE СА Part A: Prove = 2 Pick ratio v %3D DA [Show the steps.] V Pick ratio BA = 2 EA Part B: Prove (CD)/(DA) [Show the steps.] (CA)/(DA) Part C: Prove AC AB ~ ADAE [Show the steps.] (CA)/(CD) =CB Part D: Prove DE = СВ

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
Topic Video
Question

pick the answer options provided.

In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC.
B
E
A
1
CB. The proof is divided into four parts, where the title of each part
2
Below is the proof that DE =
indicates its main purpose.
Complete part D of the proof.
DE
CA
= 2
DA
Part A: Prove
Pick ratio v
[Show the steps.]
V Pick ratio
ВА
Part B: Prove
EA
(CD)/(DA)
[Show the steps.]
(CA)/(DA)
Part C: Prove ACAB ~ ADAE
[Show the steps.]
(CA)/(CD)
CB
Part D: Prove DE=
СВ
Statement
Reason
CB
Lengths of corresponding sides of similar triangles have equal ratios.
(Part C)
12
DE
Pick ratio v
CB
13
Substitution (Part A, 12)
DE
14
CB=DE
Multiply both sides of the equation by
Pick expression v
(13)
n by
Pick expression
v Pick expression
2.DE
oble
DE
(DE)/2
Transcribed Image Text:In the following triangle, point E is the midpoint of AB, and point D is the midpoint of AC. B E A 1 CB. The proof is divided into four parts, where the title of each part 2 Below is the proof that DE = indicates its main purpose. Complete part D of the proof. DE CA = 2 DA Part A: Prove Pick ratio v [Show the steps.] V Pick ratio ВА Part B: Prove EA (CD)/(DA) [Show the steps.] (CA)/(DA) Part C: Prove ACAB ~ ADAE [Show the steps.] (CA)/(CD) CB Part D: Prove DE= СВ Statement Reason CB Lengths of corresponding sides of similar triangles have equal ratios. (Part C) 12 DE Pick ratio v CB 13 Substitution (Part A, 12) DE 14 CB=DE Multiply both sides of the equation by Pick expression v (13) n by Pick expression v Pick expression 2.DE oble DE (DE)/2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Discrete Probability Distributions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning