In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH4 are burned? CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H;O(g) AH° = -802 %3D kJ/mol

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**Question 6 of 35**

In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH₄ are burned?

\[ \text{CH}_4 (g) + 2 \, \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \, \text{H}_2\text{O}(g) \]

\[\Delta H^\circ = -802 \, \text{kJ/mol}\]

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**Explanation:**

This question involves calculating the heat released during the combustion of methane (\(\text{CH}_4\)). The chemical equation provided shows the complete combustion of methane with oxygen (\( \text{O}_2 \)) to form carbon dioxide (\(\text{CO}_2\)) and water vapor (\(\text{H}_2\text{O}\)).

The enthalpy change (\(\Delta H^\circ\)) for the reaction is -802 kJ/mol, meaning that 802 kJ of heat is released for every mole of methane burned.

To find the total heat released for 2.49 moles of \(\text{CH}_4\):

\[ \text{Total Heat Released} = 2.49 \, \text{moles} \times (-802 \, \text{kJ/mol}) \]

This calculation will give the total heat energy released in kilojoules (kJ).

**Note:** Negative \(\Delta H^\circ\) indicates that the reaction is exothermic, as it releases heat.
Transcribed Image Text:**Question 6 of 35** In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH₄ are burned? \[ \text{CH}_4 (g) + 2 \, \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \, \text{H}_2\text{O}(g) \] \[\Delta H^\circ = -802 \, \text{kJ/mol}\] --- **Explanation:** This question involves calculating the heat released during the combustion of methane (\(\text{CH}_4\)). The chemical equation provided shows the complete combustion of methane with oxygen (\( \text{O}_2 \)) to form carbon dioxide (\(\text{CO}_2\)) and water vapor (\(\text{H}_2\text{O}\)). The enthalpy change (\(\Delta H^\circ\)) for the reaction is -802 kJ/mol, meaning that 802 kJ of heat is released for every mole of methane burned. To find the total heat released for 2.49 moles of \(\text{CH}_4\): \[ \text{Total Heat Released} = 2.49 \, \text{moles} \times (-802 \, \text{kJ/mol}) \] This calculation will give the total heat energy released in kilojoules (kJ). **Note:** Negative \(\Delta H^\circ\) indicates that the reaction is exothermic, as it releases heat.
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