In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH4 are burned? CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H;O(g) AH° = -802 %3D kJ/mol
In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH4 are burned? CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H;O(g) AH° = -802 %3D kJ/mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Question 6 of 35**
In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH₄ are burned?
\[ \text{CH}_4 (g) + 2 \, \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \, \text{H}_2\text{O}(g) \]
\[\Delta H^\circ = -802 \, \text{kJ/mol}\]
---
**Explanation:**
This question involves calculating the heat released during the combustion of methane (\(\text{CH}_4\)). The chemical equation provided shows the complete combustion of methane with oxygen (\( \text{O}_2 \)) to form carbon dioxide (\(\text{CO}_2\)) and water vapor (\(\text{H}_2\text{O}\)).
The enthalpy change (\(\Delta H^\circ\)) for the reaction is -802 kJ/mol, meaning that 802 kJ of heat is released for every mole of methane burned.
To find the total heat released for 2.49 moles of \(\text{CH}_4\):
\[ \text{Total Heat Released} = 2.49 \, \text{moles} \times (-802 \, \text{kJ/mol}) \]
This calculation will give the total heat energy released in kilojoules (kJ).
**Note:** Negative \(\Delta H^\circ\) indicates that the reaction is exothermic, as it releases heat.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d6b0164-700f-47c3-a14d-0f2cc5fbb356%2F3044dbc6-609a-452a-81f6-c3a4264a8b83%2Fzrm73pp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 6 of 35**
In the following reaction, how much heat (in kJ) is released when 2.49 moles of CH₄ are burned?
\[ \text{CH}_4 (g) + 2 \, \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \, \text{H}_2\text{O}(g) \]
\[\Delta H^\circ = -802 \, \text{kJ/mol}\]
---
**Explanation:**
This question involves calculating the heat released during the combustion of methane (\(\text{CH}_4\)). The chemical equation provided shows the complete combustion of methane with oxygen (\( \text{O}_2 \)) to form carbon dioxide (\(\text{CO}_2\)) and water vapor (\(\text{H}_2\text{O}\)).
The enthalpy change (\(\Delta H^\circ\)) for the reaction is -802 kJ/mol, meaning that 802 kJ of heat is released for every mole of methane burned.
To find the total heat released for 2.49 moles of \(\text{CH}_4\):
\[ \text{Total Heat Released} = 2.49 \, \text{moles} \times (-802 \, \text{kJ/mol}) \]
This calculation will give the total heat energy released in kilojoules (kJ).
**Note:** Negative \(\Delta H^\circ\) indicates that the reaction is exothermic, as it releases heat.
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