In the Figure shown below, Find (a) Find the net force on (12 nC) by 3 other charges (b) Find net potential at the location of 12 nC (c) Find the potential energy of the system of 4 charges. 2 nc - 6 nc 4 m -2 nc 4 m 90° 5 m 5 m 30 30 12 nC
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![In the Figure shown below, Find (a) Find the net force on (12 nC) by 3 other charges (b) Find
net potential at the location of 12 nC (c) Find the potential energy of the system of 4 charges.
2 nc
- 6 nC
- 2 nc
4 m
4 m
90°
5m
5 m
30 30°
12 nC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ffb9870-2903-4965-9b25-0c5e2f1ebec2%2F46739e77-b4bf-495b-893a-19dce3b044f4%2Fwnad7ns_processed.jpeg&w=3840&q=75)
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- Consider two charged particles. One charge located on the y-axis has a value -2q and is located at a distance r from the origin, point O. The other charge has a value -q and is located at a distance 2r from the origin along the x-axis. The electric potential energy of this system is equal to 0.9 kg² r -0.6- 0.3. 0.6- kq² kq² r kq² -0.9. r kq²1.0 nC + 3.0 cm / \ 3.0 cm 3.0 cm -2.0 nC -2.0 nC Oh no! That triangle is back! Except this time Prof. P was tired of that wonky 1.0 nC positive charge and replaced it with a new exciting and debonair positive 0.2 nC charge (those two boring negative charges and all the distances stayed the same). What is the electric potential energy of this too- exciting for the world arrangement of charges now (in milliJoules)?Two protons are 3.9 x 10-5 m apart. What is the electrical potential energy between the two charges? Group of answer choices 9.46 x 10^-24 J 4.76 x 10^-24 J 4.95 x 10^-24 J 5.91 x 10^-24 J 6.58 x 10^-24 J
- Find the total electric potential energy QC has due to QA & QB.Determine the initial electric potential energy of the system consisting of all four charges with q4 at infinity.Three equal point charges, each with charge 1.40 μC , are placed at the vertices of an equilateral triangle whose sides are of length 0.600 mm . What is the electric potential energy U of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)
- The drawing shows a square, each side of which has a length of L= 0.250 m. Two different positive charges q1 and q2 are fixed at the corners of the square. Find the electric potential energy of a third charge q3 = -6.00 x 10°C placed at corner A and %3D then at corner B. 41 = +1.50 x 10c 92= +4.00 x 10 cFind the change in potential energy of the system of two charges plus a third charge q3 .There is a distribution of charges as evidenced below where q₁ = +5.0 nC and q2 = -3.0 nC. If a third charge of magnitude 2.00 nC is placed between the first two charges at a distance of 15.00 cm from the origin along the x-axis, what is the potential energy of the system? You may assume that the third charge originated from an infinite distance away. Now if we wanted the potential energy of the system to be zero, where should the third charge be placed (hint: you will need to simplify and then solve a quadratic or you can use solver in excel)? Y 91 93 x=15.00 cm 92 x=30.00 cm X