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In the figure (Figure 1), two objects, O, and O2, have charges +1.0 uC and -2.0 µC respectively, and a third object, O3. is electrically neutral.

In the figure (Figure 1), two objects, O, and O2, have charges +1.0 uC and -2.0 µC respectively, and a third object, O3. is electrically neutral.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Part A In the figure (Figure 1), two objects, O1 and O2, have charges +1.0 puC and-2.0 C respectively, and a third object, O, is electrically neutral. What is the electric flux through the surface Aj that encloses all the three objects? Express your answer using two significant figures. N-m²/C Submit Request Answer Part B What is the electric flux through the surface Ag that encloses the third object only? DA Figure 1 of 1 N-m²/C Op+1.0 µC Submit Request Answer 02•-2.0 µC Provide Feedback Next> P Pearson Copyright © 2022 Pearson Education IncC. All rights reserved. | Terms of Use | Privacy Policy | Permissions| Contact Us I
Transcribed Image Text:Part A In the figure (Figure 1), two objects, O1 and O2, have charges +1.0 puC and-2.0 C respectively, and a third object, O, is electrically neutral. What is the electric flux through the surface Aj that encloses all the three objects? Express your answer using two significant figures. N-m²/C Submit Request Answer Part B What is the electric flux through the surface Ag that encloses the third object only? DA Figure 1 of 1 N-m²/C Op+1.0 µC Submit Request Answer 02•-2.0 µC Provide Feedback Next> P Pearson Copyright © 2022 Pearson Education IncC. All rights reserved. | Terms of Use | Privacy Policy | Permissions| Contact Us I
Expert Solution
Step 1

According to Gauss law, electric flux passing out of a closed surface is,

                           ∅ = qεhere q is the charge. 

 

Given,

           q1 = 1μC = 1×10-6Cq2 = -2μC  = -2×10-6Cq3 = 0 C

 

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