In the figure below, the current in the long, straight wire is I₁ = 3.90 A, and the wire lies in the plane of the rectangular loop, which carries 14.0 A. The dimensions shown are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop. magnitude N direction -Select- Q
In the figure below, the current in the long, straight wire is I₁ = 3.90 A, and the wire lies in the plane of the rectangular loop, which carries 14.0 A. The dimensions shown are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop. magnitude N direction -Select- Q
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![In the figure below, the current in the long, straight wire is \( I_1 = 3.90 \, \text{A} \), and the wire lies in the plane of the rectangular loop, which carries \( 14.0 \, \text{A} \). The dimensions shown are \( c = 0.100 \, \text{m}, a = 0.150 \, \text{m}, \) and \( \ell = 0.450 \, \text{m} \). Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.
- **Magnitude**: [Input box] N
- **Direction**: [Select box with options]
**Diagram Description**:
1. **Configuration**: The diagram consists of a straight vertical wire carrying current \( I_1 \) and a rectangular loop carrying current \( I_2 = 14.0 \, \text{A} \).
2. **Dimensions**:
- Distance \( a = 0.150 \, \text{m} \) from the straight wire to the nearest side of the loop.
- Width \( c = 0.100 \, \text{m} \) of the loop.
- Height \( \ell = 0.450 \, \text{m} \) of the loop.
3. **Currents**: Both \( I_1 \) and \( I_2 \) are directed upwards in the diagram.
The problem is to determine the net magnetic force on the loop due to the straight wire.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24227ad7-0cee-4cb3-bf8f-36b2c099999b%2F02dab9bb-0472-45d3-8f5d-9b6712436f18%2F1bvoar5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the figure below, the current in the long, straight wire is \( I_1 = 3.90 \, \text{A} \), and the wire lies in the plane of the rectangular loop, which carries \( 14.0 \, \text{A} \). The dimensions shown are \( c = 0.100 \, \text{m}, a = 0.150 \, \text{m}, \) and \( \ell = 0.450 \, \text{m} \). Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.
- **Magnitude**: [Input box] N
- **Direction**: [Select box with options]
**Diagram Description**:
1. **Configuration**: The diagram consists of a straight vertical wire carrying current \( I_1 \) and a rectangular loop carrying current \( I_2 = 14.0 \, \text{A} \).
2. **Dimensions**:
- Distance \( a = 0.150 \, \text{m} \) from the straight wire to the nearest side of the loop.
- Width \( c = 0.100 \, \text{m} \) of the loop.
- Height \( \ell = 0.450 \, \text{m} \) of the loop.
3. **Currents**: Both \( I_1 \) and \( I_2 \) are directed upwards in the diagram.
The problem is to determine the net magnetic force on the loop due to the straight wire.
Transcribed Image Text:The image shows a dropdown menu with several directional options. The menu includes the following items:
- "---Select---"
- "upward"
- "downward"
- "to the left"
- "to the right"
- "into the page"
- "out of the page"
This dropdown menu allows users to select a direction, which can be useful in educational tools for teaching concepts related to vectors, motion, or spatial orientation.
Expert Solution
Step 1
The required force due to the field generated by the current carrying wire on the closed loop is given by:
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