In the figure below, Q₁ (-6 µC) by Q₂ (2 μC) are shown. Use k=9x10⁹ Nm²/c². Q1 O x=0 Q2 x=3cm x=4cm Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁1. Therefore, |E₂|> |E₁|. Both fields point in the negative x- direction. E₁ X E2 x=3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: 6x107N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 18x107N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet 24x10' N/C Hint: Don't forget the sign of the electric fields.

In the figure below, Q₁ (-6 µC) by Q₂ (2 μC) are shown. Use k=9x10⁹ Nm²/c². Q1 O x=0 Q2 x=3cm x=4cm Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁1. Therefore, |E₂|> |E₁|. Both fields point in the negative x- direction. E₁ X E2 x=3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: 6x107N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 18x107N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet 24x10' N/C Hint: Don't forget the sign of the electric fields.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

In the figure below, Q₁ (-6 µC) by Q₂ (2 μC) are shown.
Use k=9x10⁹ Nm²/C².
Q1
x=0
Q2
x=3cm x 4cm
Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to
the point x=3 cm compared to Q₁. Therefore, |E2| > |E₁. Both fields point in the negative x-
direction.
E₁
X
E2
x=3cm
(a) Calculate the electric field E₁ due to Q₁ at x = 3 cm.
N/C
E₁: 6x107
(b) Calculate the electric field E₂ due to Q₂ at x = 3 cm.
E₂: 18x107 N/C
(c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂.
E.
N/C
net 24x107x
Hint: Don't forget the sign of the electric fields.

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