In the Figure below a block slides along a path that is without friction until the block reaches the section of length L = 0.75 m, which begins at height h = 2 m on a ramp of angle 0 = 30°. In that section, the coefficient of kinetic friction is 0.40. The block passes through point A with a speed of 8 m/sec. What is the speed of the block at point B (where the friction ends)? Answer: 3.5 m/sec B 0

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Chapter1: Units, Trigonometry. And Vectors
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KE = ½-mv², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E¡ = Ef,
Wfric=Ffricd, Ffric = HkN, E₁-Wfric = Ef
Problem 1:
In the Figure below a block slides along a path that is without friction until the block reaches
the section of length L = 0.75 m, which begins at height h = 2 m on a ramp of angle 0 = 30°.
In that section, the coefficient of kinetic friction is 0.40. The block passes through point A with a
speed of 8 m/sec. What is the speed of the block at point B (where the friction ends)?
Answer: 3.5 m/sec
h
Ꮎ
Transcribed Image Text:KE = ½-mv², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E¡ = Ef, Wfric=Ffricd, Ffric = HkN, E₁-Wfric = Ef Problem 1: In the Figure below a block slides along a path that is without friction until the block reaches the section of length L = 0.75 m, which begins at height h = 2 m on a ramp of angle 0 = 30°. In that section, the coefficient of kinetic friction is 0.40. The block passes through point A with a speed of 8 m/sec. What is the speed of the block at point B (where the friction ends)? Answer: 3.5 m/sec h Ꮎ
KE = ½-mv², Ug = mgh, U₁ = ½kx², E = KE + Ug + Us, Ei = Eƒ,
Wfric=Ffricd,
Ffric = MkN, E₁ - Wfric = Ef
Transcribed Image Text:KE = ½-mv², Ug = mgh, U₁ = ½kx², E = KE + Ug + Us, Ei = Eƒ, Wfric=Ffricd, Ffric = MkN, E₁ - Wfric = Ef
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