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In the figure battery 1 has emf 81 = 23.0 V and internal resistance r₁ = 0.0172 and battery 2 has emf 82 = 23.0 V and internal resistance r₂ = 0.012 02. The batteries are connected series with an external resistance R. (a) What R value makes the terminal-to- terminal potential difference of one of the batteries zero? (b) Which battery is that?

In the figure battery 1 has emf 81 = 23.0 V and internal resistance r₁ = 0.0172 and battery 2 has emf 82 = 23.0 V and internal resistance r₂ = 0.012 02. The batteries are connected series with an external resistance R. (a) What R value makes the terminal-to- terminal potential difference of one of the batteries zero? (b) Which battery is that?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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In the figure, battery 1 has an electromotive force (emf) \( \mathcal{E}_1 = 23.0 \, \text{V} \) and an internal resistance \( r_1 = 0.017 \, \Omega \). Battery 2 has an emf \( \mathcal{E}_2 = 23.0 \, \text{V} \) and an internal resistance \( r_2 = 0.012 \, \Omega \). The batteries are connected in series with an external resistance \( R \). (a) What \( R \) value makes the terminal-to-terminal potential difference of one of the batteries zero? (b) Which battery is that? **Diagram Explanation:** The diagram shows a simple electrical circuit with two batteries connected in series. Each battery is represented as a cell with its respective emf and internal resistance. The circuit continues from the batteries through an external resistor labeled \( R \). Each battery is connected with its positive terminal at the top and negative at the bottom, and arrows are used to denote the direction of emf for each battery (\( \mathcal{E}_1 \) and \( \mathcal{E}_2 \)).
Transcribed Image Text:In the figure, battery 1 has an electromotive force (emf) \( \mathcal{E}_1 = 23.0 \, \text{V} \) and an internal resistance \( r_1 = 0.017 \, \Omega \). Battery 2 has an emf \( \mathcal{E}_2 = 23.0 \, \text{V} \) and an internal resistance \( r_2 = 0.012 \, \Omega \). The batteries are connected in series with an external resistance \( R \). (a) What \( R \) value makes the terminal-to-terminal potential difference of one of the batteries zero? (b) Which battery is that? **Diagram Explanation:** The diagram shows a simple electrical circuit with two batteries connected in series. Each battery is represented as a cell with its respective emf and internal resistance. The circuit continues from the batteries through an external resistor labeled \( R \). Each battery is connected with its positive terminal at the top and negative at the bottom, and arrows are used to denote the direction of emf for each battery (\( \mathcal{E}_1 \) and \( \mathcal{E}_2 \)).
Expert Solution
Step 1

Given:

         E1 = 23 v

        r1 = 0.017 Ω

       E2 = 23 v

       r2 = 0.012 Ω

       External resistance = RPhysics homework question answer, step 1, image 1

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