In the figure, a spring of spring constant 2.80 x 10ª N/m is between a rigid beam and the output piston of a hydraulic lever. An empty container with negligible mass sits on the input piston. The input piston has area A¡, and the output piston has area 28.0A;. Initially the spring is at its rest length. How many kilograms of sand must be (slowly) poured into the container to compress the spring by 4.40 cm? Beam Container Spring Number i Units

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In the figure, a spring with a spring constant of \(2.80 \times 10^4 \, \text{N/m}\) is placed between a rigid beam and the output piston of a hydraulic lever. An empty container with negligible mass is positioned on the input piston. The input piston has an area \(A_i\), and the output piston has an area \(28.0A_i\). Initially, the spring is at its rest length. The question asks how many kilograms of sand must be slowly added to the container to compress the spring by 4.40 cm.

**Diagram Explanation:**

The diagram shows the setup with a hydraulic lever system. On the left, there is a container labeled "Container" resting on the input piston. The hydraulic lever is illustrated with two connected chambers filled with a fluid. A spring labeled "Spring" is situated between a "Beam" and the output piston on the right side. The diagram visually represents the physical arrangement described in the problem statement.

**Problem Requirements:**

- **Spring Constant:** \(2.80 \times 10^4 \, \text{N/m}\)
- **Compression Distance:** 4.40 cm (converted to meters in calculations: 0.044 m)
- **Input Piston Area:** \(A_i\)
- **Output Piston Area:** \(28.0A_i\)

**Solution Steps:**

To solve the problem:

1. Calculate the force required to compress the spring by 0.044 m using Hooke's law: \(F = k \cdot x\).
2. Determine the equivalent force needed on the input side using the area ratio: \(F_{\text{input}} = \frac{F}{28.0}\).
3. Convert the force to mass using the gravitational constant: \(m = \frac{F_{\text{input}}}{g}\) where \(g = 9.81 \, \text{m/s}^2\).

**Input Fields:**

- **Number:** Enter the mass of sand required in kilograms.
- **Units:** Select the appropriate unit (kilograms).
Transcribed Image Text:In the figure, a spring with a spring constant of \(2.80 \times 10^4 \, \text{N/m}\) is placed between a rigid beam and the output piston of a hydraulic lever. An empty container with negligible mass is positioned on the input piston. The input piston has an area \(A_i\), and the output piston has an area \(28.0A_i\). Initially, the spring is at its rest length. The question asks how many kilograms of sand must be slowly added to the container to compress the spring by 4.40 cm. **Diagram Explanation:** The diagram shows the setup with a hydraulic lever system. On the left, there is a container labeled "Container" resting on the input piston. The hydraulic lever is illustrated with two connected chambers filled with a fluid. A spring labeled "Spring" is situated between a "Beam" and the output piston on the right side. The diagram visually represents the physical arrangement described in the problem statement. **Problem Requirements:** - **Spring Constant:** \(2.80 \times 10^4 \, \text{N/m}\) - **Compression Distance:** 4.40 cm (converted to meters in calculations: 0.044 m) - **Input Piston Area:** \(A_i\) - **Output Piston Area:** \(28.0A_i\) **Solution Steps:** To solve the problem: 1. Calculate the force required to compress the spring by 0.044 m using Hooke's law: \(F = k \cdot x\). 2. Determine the equivalent force needed on the input side using the area ratio: \(F_{\text{input}} = \frac{F}{28.0}\). 3. Convert the force to mass using the gravitational constant: \(m = \frac{F_{\text{input}}}{g}\) where \(g = 9.81 \, \text{m/s}^2\). **Input Fields:** - **Number:** Enter the mass of sand required in kilograms. - **Units:** Select the appropriate unit (kilograms).
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