In the drawings below, "CO" represents a carbonyl group (C=O). Which compound below will undergo decarboxylation (loss of CO₂) upon being heated to approximately 60 °C ? O CH3-CH2-CH2-CH2-CO-CO-OH O CH3-CO-CH2-CH,-CH2-CO-OH Q CH3-CH2-CO-CH2-CH2-CO-OH © CH3-CH2-CH2-CO-CH2-CO-OH

In the drawings below, "CO" represents a carbonyl group (C=O). Which compound below will undergo decarboxylation (loss of CO₂) upon being heated to approximately 60 °C ? O CH3-CH2-CH2-CH2-CO-CO-OH O CH3-CO-CH2-CH,-CH2-CO-OH Q CH3-CH2-CO-CH2-CH2-CO-OH © CH3-CH2-CH2-CO-CH2-CO-OH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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In the drawings below, "CO" represents a carbonyl group (C=O).
Which compound below will undergo decarboxylation
(loss of CO₂) upon being heated to approximately 60 °C ?
© CH3-CH2-CH2-CH2-CO-CO-OH
O CH3-CO-CH2-CH2-CH2-CO-OH
Q CH3-CH2-CO-CH2-CH2-CO-OH
O CH3-CH,-CH,-CO-CH,-CO-OH

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The equivalence point is defined as moles acid = moles base. So first, let's calculate the initial moles of base we used. molpase Mpase = Volsoiution Molarity base = 0.100 (M) Volume of solution= _50.00 mL Moles of base = _5.00 mmol So, we need 5.00 mmol of acid (titrant) to be delivered to the analyte. Since we know the molarity of the acid and moles of acid, we just need to solve for the volume of acid (titrant) to be added. molacid Voladded Macid Molarity acid = . 0.200 (M) Moles of acid = _5.00 (mmol) Volume of acid needed to reach equivalence point (mL)
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