In the diesel engine experiment, if: engine speed= 1302 Torque (N.m) = 9.9 Power(W)= 1344 Air mass flow rate (Kg/sec) = 0.002178 fuel mass flow rate (Kg/sec) = 0.000140 Tamb (C)= 20.1 Texh (C)= 292 Pamb (mbar)= 929 Air box Pressure (Pa)= -82 The Volumetric efficiency will be:

In the diesel engine experiment, if: engine speed= 1302 Torque (N.m) = 9.9 Power(W)= 1344 Air mass flow rate (Kg/sec) = 0.002178 fuel mass flow rate (Kg/sec) = 0.000140 Tamb (C)= 20.1 Texh (C)= 292 Pamb (mbar)= 929 Air box Pressure (Pa)= -82 The Volumetric efficiency will be:

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

In the diesel engine experiment, if:
engine speed= 1302
Torque (N.m) = 9.9
Power(W)= 1344
Air mass flow rate (Kg/sec) = 0.002178
fuel mass flow rate (Kg/sec) = 0.000140
Tamb (C)= 20.1
Texh (C)= 292
Pamb (mbar)= 929
Air box Pressure (Pa)= -82
The Volumetric efficiency will be:
Select one:
a. 84.89%
O b. 78.33%
O c. 65.27%
O d. 71.86%

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