In the diagram, QU - 120, SU -50, and RS - ST - TU, Find the indicated values. 7) RS 8) RT 9) QS

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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## Transcription for Educational Website

### Geometry Problem and Solution

**Problem Description:**

In the given diagram, \( QU = 120 \), \( SU = 50 \), and \( RS = ST \). Your task is to find the indicated values.

- \( RS = 3x - 16 \)
- \( ST = 4x - 8 \)
- \( RT = 60 \)

**Steps to Solve:**

1. **Equation Setup:**
   - Identify that point \( S \) is between points \( R \) and \( T \) on the line segment \( RT \). Utilize this information to write equations in terms of \( x \).
   - Given:
     \[
     RS = 3x - 16
     \]
     \[
     ST = 4x - 8
     \]
   - Note that \( RS + ST = RT \).

2. **Equation Solution:**
   - Write the equation:
     \[
     (3x - 16) + (4x - 8) = 60
     \]
   - Combine like terms:
     \[
     7x - 24 = 60
     \]
   - Add 24 to both sides:
     \[
     7x = 84
     \]
   - Divide by 7:
     \[
     x = 12
     \]
   - Substitute back to find \( RS \) and \( ST \):
     \[
     RS = 3(12) - 16 = 36 - 16 = 20
     \]
     \[
     ST = 4(12) - 8 = 48 - 8 = 40
     \]

**Graph Explanation:**

- There is a simple line diagram with points marked as \( R \), \( S \), and \( T \).
- \( R \) is on the leftmost end, followed by \( S \), and \( T \) on the right, showing a linear arrangement.

**Map Image:**

- The assignment also includes a small black and white map depicting a geographical region with labeled borders but no additional context or captions relevant to the geometry problem.

### Conclusion

Through these steps, you determined the measures of \( RS \) and \( ST \) as 20 and 40 units, respectively, given the constraints of the problem and the equation \( x =
Transcribed Image Text:## Transcription for Educational Website ### Geometry Problem and Solution **Problem Description:** In the given diagram, \( QU = 120 \), \( SU = 50 \), and \( RS = ST \). Your task is to find the indicated values. - \( RS = 3x - 16 \) - \( ST = 4x - 8 \) - \( RT = 60 \) **Steps to Solve:** 1. **Equation Setup:** - Identify that point \( S \) is between points \( R \) and \( T \) on the line segment \( RT \). Utilize this information to write equations in terms of \( x \). - Given: \[ RS = 3x - 16 \] \[ ST = 4x - 8 \] - Note that \( RS + ST = RT \). 2. **Equation Solution:** - Write the equation: \[ (3x - 16) + (4x - 8) = 60 \] - Combine like terms: \[ 7x - 24 = 60 \] - Add 24 to both sides: \[ 7x = 84 \] - Divide by 7: \[ x = 12 \] - Substitute back to find \( RS \) and \( ST \): \[ RS = 3(12) - 16 = 36 - 16 = 20 \] \[ ST = 4(12) - 8 = 48 - 8 = 40 \] **Graph Explanation:** - There is a simple line diagram with points marked as \( R \), \( S \), and \( T \). - \( R \) is on the leftmost end, followed by \( S \), and \( T \) on the right, showing a linear arrangement. **Map Image:** - The assignment also includes a small black and white map depicting a geographical region with labeled borders but no additional context or captions relevant to the geometry problem. ### Conclusion Through these steps, you determined the measures of \( RS \) and \( ST \) as 20 and 40 units, respectively, given the constraints of the problem and the equation \( x =
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