In the diagram below, FG is parallel to CD. If CD is twice the length of FE, CE = 28, and FG = 14, find the length of FE, Figures are not necessarily drawn to scale. State your answer in simplest radical form, if necessary. %3D %3D Answer: FE= Submit Answer

In the diagram below, FG is parallel to CD. If CD is twice the length of FE, CE = 28, and FG = 14, find the length of FE, Figures are not necessarily drawn to scale. State your answer in simplest radical form, if necessary. %3D %3D Answer: FE= Submit Answer

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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**Solve for Side, Similar Triangles (Distribution)**

**Date & Time:** Oct 21, 7:15:36 PM

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**Problem Statement:**

In the diagram below, \( FG \) is parallel to \( CD \). If \( CD \) is twice the length of \( FE \), \( CE = 28 \), and \( FG = 14 \), find the length of \( FE \). Figures are not necessarily drawn to scale. State your answer in simplest radical form, if necessary.

**Diagram Description:**

The diagram shows a triangle \( CDE \) with a parallel line \( FG \) intersecting the other sides. Line \( FG \) is parallel to the base \( CD \). The given points are labeled appropriately.

**Solution Box:**

Answer: \( FE = \) [Input box to enter answer]

**Button:**

[Submit Answer]

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