In the diagram, AJCQ- ATYA Find the value of x. 30 36 40 24 A 32 O27 O26 36 28

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement**:
In the diagram, \( \triangle JCQ \sim \triangle TYA \). Find the value of \( x \).

**Diagram Details**:
There are two triangles in the diagram:

1. **Triangle JCQ**:
   - Side \( JC = 36 \)
   - Side \( CQ = 40 \)
   - Side \( JQ = 32 \)

2. **Triangle TYA**:
   - Side \( TY = x \)
   - Side \( YA = 30 \)
   - Side \( TA = 24 \)

**Options**:
A multiple-choice list is provided to find the value of \( x \):
- 27
- 26
- 36
- 28

**Explanation**:

Given that \( \triangle JCQ \sim \triangle TYA \), this means that the two triangles are similar and hence, their corresponding sides are proportional. This similarity can be expressed by the proportion of corresponding side lengths:

\[
\frac{JC}{TY} = \frac{JQ}{TA}
\]

Given the side lengths for triangular relationships:

\[
\frac{36}{x} = \frac{32}{24}
\]

Cross-multiplying to solve for \( x \),

\[
36 \times 24 = 32 \times x
\]

\[
864 = 32x
\]

\[
x = \frac{864}{32}
\]

\[
x = 27
\]

Thus the value of \( x \) is 27.

**Answer**: 27
Transcribed Image Text:**Problem Statement**: In the diagram, \( \triangle JCQ \sim \triangle TYA \). Find the value of \( x \). **Diagram Details**: There are two triangles in the diagram: 1. **Triangle JCQ**: - Side \( JC = 36 \) - Side \( CQ = 40 \) - Side \( JQ = 32 \) 2. **Triangle TYA**: - Side \( TY = x \) - Side \( YA = 30 \) - Side \( TA = 24 \) **Options**: A multiple-choice list is provided to find the value of \( x \): - 27 - 26 - 36 - 28 **Explanation**: Given that \( \triangle JCQ \sim \triangle TYA \), this means that the two triangles are similar and hence, their corresponding sides are proportional. This similarity can be expressed by the proportion of corresponding side lengths: \[ \frac{JC}{TY} = \frac{JQ}{TA} \] Given the side lengths for triangular relationships: \[ \frac{36}{x} = \frac{32}{24} \] Cross-multiplying to solve for \( x \), \[ 36 \times 24 = 32 \times x \] \[ 864 = 32x \] \[ x = \frac{864}{32} \] \[ x = 27 \] Thus the value of \( x \) is 27. **Answer**: 27
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