seeking for help on this qns again since i'm still confused by what the previous tutor commented in his solution here. hope to get help from a new tutor this time. 1.png is the qns while 2.png is the solution provided by the previous tutor but i do not quite get the part i mentioned 'Do not quite understand this' Slope of line AB is m= -tandpont on line AB: (5,3)so equation of line AB will be given byy-3 = m[x-5)y-3 --tano (x-5)(x -5)%3Dsinoy-3 =Cosoy coso-3x sino +y coso – (3cos0+5sinB) =0As we_know distauce of point (xs ye from+C =0 is given byax, + by, +C\.-3coso xsin B + 5sino**line ax +x+by+CDo not quiteunderstand this.d In the diagram, A is a point on the x-axis and B is a point on the y-axis such that (5, 3) lies on the straightline passing through A and B.(5, 3)A(i) Given that OP is perpendicular to AB and ZBAO = 0, show that OP = 3 cos 0 + 5 sin 0.

Answered: Image /qna-images/answer/fa182190-ab44-4e57-a3c2-f0ab4e33f0af.jpg

In the diagram, A is a point on the x-axis and B is a point on the y-axis such that (5, 3) lies on the straight line passing through A and B. B (5,3) (i) Given that OP is perpendicular to AB and ZBAO = 0, show that OP = 3 cos 0 + 5 sin 0. %3D

In the diagram, A is a point on the x-axis and B is a point on the y-axis such that (5, 3) lies on the straight line passing through A and B. B (5,3) (i) Given that OP is perpendicular to AB and ZBAO = 0, show that OP = 3 cos 0 + 5 sin 0. %3D

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

seeking for help on this qns again since i'm still confused by what the previous tutor commented in his solution here. hope to get help from a new tutor this time. 1.png is the qns while 2.png is the solution provided by the previous tutor but i do not quite get the part i mentioned 'Do not quite understand this'

Slope of line AB is m= -tand
pont on line AB: (5,3)
so equation of line AB will be given by
y-3 = m[x-5)
y-3 --tano (x-5)
(x -5)
%3D
sino
y-3 =
Coso
y coso-3
x sino +y coso – (3cos0+5sinB) =0
As we_know distauce of point (xs ye from
+C =0 is given by
ax, + by, +C\.
-3coso xsin B + 5sino
**
line ax +
x+by+C
Do not quite
understand this.
d

In the diagram, A is a point on the x-axis and B is a point on the y-axis such that (5, 3) lies on the straight
line passing through A and B.
(5, 3)
A
(i) Given that OP is perpendicular to AB and ZBAO = 0, show that OP = 3 cos 0 + 5 sin 0.

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