In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 - P(X ≤ 3/8). O True O False |||||||||||||| 3-52. The thickness of wood paneling (in inches) that a customer orders is a random variable with the following cumu- lative distribution function: 0 0.2 F(x)= 0.9 1 x < 1/8 1/81/4) (e) P(X≤1/2) f(¹18) = P( X = 1/8)= 0.20 f(1/4) - P(X= 1/4)= 0.70 f (3/8)= P(X= 9/8)= 0.10 11111111

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In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 - P(X ≤ 3/8).
O True
O False
||||||||||||
3-52. The thickness of wood paneling (in inches) that a
customer orders is a random variable with the following cumu-
lative distribution function:
0.2
F(x)= 0.9
1
x < 1/8
1/8<x< 1/4
1/4≤x<3/8
3/8 ≤ x
Determine the following probabilities:
(a) P(X ≤1/18) (b) P(X ≤1/4) (c) P(X≤5/16)
(d) P(X>1/4) (e) P(X≤1/2)
f(¹18) = P(X=1/8)= 0.20
f(1/4) = P(X= 1/4) = 0.70
f (3/8)= P(X - 9/8)= 0.10
1111111
Transcribed Image Text:In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 - P(X ≤ 3/8). O True O False |||||||||||| 3-52. The thickness of wood paneling (in inches) that a customer orders is a random variable with the following cumu- lative distribution function: 0.2 F(x)= 0.9 1 x < 1/8 1/8<x< 1/4 1/4≤x<3/8 3/8 ≤ x Determine the following probabilities: (a) P(X ≤1/18) (b) P(X ≤1/4) (c) P(X≤5/16) (d) P(X>1/4) (e) P(X≤1/2) f(¹18) = P(X=1/8)= 0.20 f(1/4) = P(X= 1/4) = 0.70 f (3/8)= P(X - 9/8)= 0.10 1111111
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