May you give me the explaination and answer for these 2 please? Triangle GHJ with vertices G(-2, 4), H(3, 6), and J(3, -2) is dilated by a factor of !centered at the origin. What are thecoordinates of G' after the dilation?O .E:В.O .(-)(-)OD. In the coordinate plane, line p has slope 8 and y-intercept (0, 5). Line r is the result of dilating line p by a factor of 3 withcenter (0, 3). What are the slope and y-intercept of line r?O A. Line r has slope 5 and y-intercept (0, 2).O B. Line r has slope 8 and y-intercept (0, 5).C. Line r has slope 8 and y-intercept (0, 9).D. Line r has slope 11 and y-intercept (0, 8).

(1) Coordinates of G are (-2,4) We know that coordinates of the point (x,y) after dilation by factor of k centered at origin is (kx,ky) Therefore, coordinates of G' are13×(-2),13×4 that is -23,43(2) Equation of line p is y=mx+b where m is slope of line and b is y-intercept, Equation of line is y=8x+5 We know that coordinates of the point (x,y) after dilation by factor k centered at (a,b) is k(x-a)+a,k(y-b)+b) Therefore, coordinate of the point (0,5) after dilation is 3(0-0)+0,3(5-3)+3, that is (0,9) Point (0,3) does not lie on the line, so the line r after dilation is parallel to the line p, So slope of line r is 8 and y-intercept is (0,9) Ans: (1) G'-23,43 (2) Line r has slope 8 and y-intercept at (0,9)