In the compound interest example on P.344. Calculate S20 and T240. Which is the better investment after 20 years?

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Author:Randall Billingsley, Lawrence J. Gitman, Michael D. Joehnk
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Chapter4: Managing Your Cash And Savings
Section: Chapter Questions
Problem 7FPE: Calculating interest earned and future value of savings account. If you put 6,000 in a savings...
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In the compound interest example on P.344. Calculate S20 and T240. Which is the better investment after 20 years?

Hence,
S40 = (1.11)"(10 090.090 909. ..)
(9 090.909 090...)
= (65.000 867...)(10 090.090 909...)
(9 090.909 090. ..)
655 917.842...
(9 090.909 090...)
e $646 826.
// Can that be right? You put in $40,000 and take out > $600,000 in interest.
Now consider Plan B and let T, denote the number of dollars in the plan after
(exactly) n months of operation. Then To = $100 and
Tn+1 – T,+ interest on T,
+$100
-
= T,+(1/12) of 10% of T„+$100
= T„[1+0.1/12]
+$100.
%3D
100
In this RE, a = 12.1/12,
c = 100, so
1 -
-12000 and
-0.1/12
a
T, = (12.1/12)"[100+12000] – 12000.
Hence, after 40 × 12 months,
T480 = (12.1/12)4" (12100)
= (1.008 333...)+8° (12100) - (12000)
= (53.700 663...)(12100)
= 649 778.023 4...
e $637 778.
- (12000)
480
- (12000)
- (12000)
Therefore, Plan A has a slightly larger value after 40 years.
Transcribed Image Text:Hence, S40 = (1.11)"(10 090.090 909. ..) (9 090.909 090...) = (65.000 867...)(10 090.090 909...) (9 090.909 090. ..) 655 917.842... (9 090.909 090...) e $646 826. // Can that be right? You put in $40,000 and take out > $600,000 in interest. Now consider Plan B and let T, denote the number of dollars in the plan after (exactly) n months of operation. Then To = $100 and Tn+1 – T,+ interest on T, +$100 - = T,+(1/12) of 10% of T„+$100 = T„[1+0.1/12] +$100. %3D 100 In this RE, a = 12.1/12, c = 100, so 1 - -12000 and -0.1/12 a T, = (12.1/12)"[100+12000] – 12000. Hence, after 40 × 12 months, T480 = (12.1/12)4" (12100) = (1.008 333...)+8° (12100) - (12000) = (53.700 663...)(12100) = 649 778.023 4... e $637 778. - (12000) 480 - (12000) - (12000) Therefore, Plan A has a slightly larger value after 40 years.
Example 8.2.3: Compound Interest
Suppose you are offered two retirement savings plans. In Plan A, you start with
$1,000, and each year (on the anniversary of the plan), you are paid 11% simple
interest, and you add $1,000. In Plan B, you start with $100, and each month, you
are paid one-twelfth of 10% simple (annual) interest, and you add $100. Which plan
will be larger after 40 years?
Consider Plan A and let S, denote the number of dollars in the plan after
(exactly) n years of operation. Then So = $1,000 and
// Can we apply a recurrence equation?
Sn+1 = Sn +interest on S,+ $1000
= S„ +11% of S,
= S„(1+0.11)
+$1000
+ $1000.
1000
In this RE, a = 1.11, c = 1000, so
1
and
- a
-0.11
1000
1000
Sn = (1.11)" | 1000
-0.11
-0.11
1110
1000
(1.11)"
[+0.11]
+0.11
Transcribed Image Text:Example 8.2.3: Compound Interest Suppose you are offered two retirement savings plans. In Plan A, you start with $1,000, and each year (on the anniversary of the plan), you are paid 11% simple interest, and you add $1,000. In Plan B, you start with $100, and each month, you are paid one-twelfth of 10% simple (annual) interest, and you add $100. Which plan will be larger after 40 years? Consider Plan A and let S, denote the number of dollars in the plan after (exactly) n years of operation. Then So = $1,000 and // Can we apply a recurrence equation? Sn+1 = Sn +interest on S,+ $1000 = S„ +11% of S, = S„(1+0.11) +$1000 + $1000. 1000 In this RE, a = 1.11, c = 1000, so 1 and - a -0.11 1000 1000 Sn = (1.11)" | 1000 -0.11 -0.11 1110 1000 (1.11)" [+0.11] +0.11
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