In the circuit shown, the potential difference VA VB = 41.0 V and the resistance R₁ = R₂ = R3 = R4 = 155 №. The arrows for currents IA and I indicate the direction of positive current flow. The arrows do not necessarily indicate the direction of the actual current flow at those points. Determine the current IA. IA = 0.265 IB = Incorrect Determine the current IB. 0.794 A A R₁ V. R₁ www R₂ www R₂ www
In the circuit shown, the potential difference VA VB = 41.0 V and the resistance R₁ = R₂ = R3 = R4 = 155 №. The arrows for currents IA and I indicate the direction of positive current flow. The arrows do not necessarily indicate the direction of the actual current flow at those points. Determine the current IA. IA = 0.265 IB = Incorrect Determine the current IB. 0.794 A A R₁ V. R₁ www R₂ www R₂ www
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
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Question

Transcribed Image Text:In the circuit shown, the potential difference
VA VB = 41.0 V and the resistance
R₁ = R₂ = R3 = R4 = 155 №. The arrows for currents IA
and I indicate the direction of positive current flow. The
arrows do not necessarily indicate the direction of the actual
current flow at those points.
Determine the current IA.
IA =
0.265
IB =
Incorrect
Determine the current IB.
0.794
A
A
R₁
www
V.
R₁
www
R₂
www
R₂
www
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