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In the circuit shown, the component values are: C = 100nF, L = 10μH, and R₁ = R₂ = 10. The two voltage sources produce V₁ (t) =10sin (106t) V, V₂ (t) =6cos(106t+ 90°) V. Write the phasor form of the current through the second voltage source in polar form as IB = |IB|e¹4³. Provide the value of IÂ | in milli-Amps (mA). V₁ C L R₁ R₂ IB V₂

In the circuit shown, the component values are: C = 100nF, L = 10μH, and R₁ = R₂ = 10. The two voltage sources produce V₁ (t) =10sin (106t) V, V₂ (t) =6cos(106t+ 90°) V. Write the phasor form of the current through the second voltage source in polar form as IB = |IB|e¹4³. Provide the value of IÂ | in milli-Amps (mA). V₁ C L R₁ R₂ IB V₂

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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In the circuit shown, the component values are: C = 100nF, L = 10μH, and R₁ = R₂ = 10. The two voltage sources produce V₁ (t) =10sin (106t) V, V₂ (t) =6cos(106t+ 90°) V. Write the phasor form of the current through the second voltage source in polar form as IB = |IB|e¹4³. Provide the value of IÂ | in milli-Amps (mA). V₁ C L R₁ R₂ IB V₂
Transcribed Image Text:In the circuit shown, the component values are: C = 100nF, L = 10μH, and R₁ = R₂ = 10. The two voltage sources produce V₁ (t) =10sin (106t) V, V₂ (t) =6cos(106t+ 90°) V. Write the phasor form of the current through the second voltage source in polar form as IB = |IB|e¹4³. Provide the value of IÂ | in milli-Amps (mA). V₁ C L R₁ R₂ IB V₂
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