In the circuit shown below, R = 200.0 Q, C = 6.00 µF and the AC source is given by e = 170.0 sin (377t), where e is in volts and t is in seconds. The magnitude of phase angle between the current and the source voltage is: (AC) R O a. 65.6 degrees O b. 35.0 degrees O c. 45.0 degrees O d. 60.0 degrees O e. 72.4 degrees

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In the circuit shown below, R= 200.0 2, C = 6.00 µE and the AC source is given by
8 = 170.0 sin (377t), where ɛ is in volts and t is in seconds. The magnitude of phase angle
between the current and the source voltage is:
H
(AC
R
O a. 65.6 degrees
O b. 35.0 degrees
Oc.
45.0 degrees
O d. 60.0 degrees
O e.
72.4 degrees
Transcribed Image Text:In the circuit shown below, R= 200.0 2, C = 6.00 µE and the AC source is given by 8 = 170.0 sin (377t), where ɛ is in volts and t is in seconds. The magnitude of phase angle between the current and the source voltage is: H (AC R O a. 65.6 degrees O b. 35.0 degrees Oc. 45.0 degrees O d. 60.0 degrees O e. 72.4 degrees
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