In the circuit in the figure, Vcc = 18 V, Rs1 = 0.9 kΩ, Rs2 = 0.5 kΩ, R1 = 75 kΩ, R2 = 15 kΩ, RC = 2.2 kΩ, RE = 1 kΩ and β =120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = Cπ = 48 pF and Cce = 11 pF. Accordingly, considering the frequency response of the circuit, what would be the high cutoff frequency (fH)? NOTE-1: The output impedance of the transistor is r0 = 20 kΩ and will be taken into account in the calculations. NOTE-2: The high frequency dependence of hfe, β, will be taken into account. a. 719,95 kHz b. 143,99 kHz c. 48,00 kHz d. 191,99 kHz e. 575,96 kHz f. 479,97 kHz g. 335,98 kHz h. 623,96 kHz

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In the circuit in the figure, Vcc = 18 V, Rs1 = 0.9 kΩ, Rs2 = 0.5 kΩ, R1 = 75 kΩ, R2 = 15 kΩ, RC = 2.2 kΩ, RE = 1 kΩ and β =120. It is also known that Cwi = 6 pF, Cwo = 10 pF, Cbc = Cu = 7 pF, Cbe = Cπ = 48 pF and Cce = 11 pF. Accordingly, considering the frequency response of the circuit, what would be the high cutoff frequency (fH)?

NOTE-1: The output impedance of the transistor is r0 = 20 kΩ and will be taken into account in the calculations.

NOTE-2: The high frequency dependence of hfe, β, will be taken into account.

a.
719,95 kHz
b.
143,99 kHz
c.
48,00 kHz
d.
191,99 kHz
e.
575,96 kHz
f.
479,97 kHz
g.
335,98 kHz
h.
623,96 kHz
Vcc
R1
RC
C3
Vo
1µF
C1
Rs2
C2
Q1
Vi-
NPN
1µF
1µF
Rs1
R2
RE
CE
10µF
Transcribed Image Text:Vcc R1 RC C3 Vo 1µF C1 Rs2 C2 Q1 Vi- NPN 1µF 1µF Rs1 R2 RE CE 10µF
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