In the circuit below there are three lamps connected in parallel V L1 L2 L3 The voltage of the battery is 120 Volts. The three lamps have a NOMINAL voltage of 120V but different power: P(L1)=600W, P(L2)=1200W, P(L3)=300W. Calculate the current on the Battery

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**Parallel Circuit with Three Lamps**

In the circuit below, there are three lamps connected in parallel:

- **Diagram Description**: The diagram shows a battery with a voltage \( V \), labeled as 120 Volts. Three lamps, labeled as L1, L2, and L3, are connected in parallel to the battery.

**Lamp Specifications:**

- The voltage of the battery is 120 Volts.
- Each lamp has a nominal voltage of 120 volts, but they have different power ratings:
  - \( P(L1) = 600 \, \text{W} \)
  - \( P(L2) = 1200 \, \text{W} \)
  - \( P(L3) = 300 \, \text{W} \)

**Task:**

Calculate the current drawn from the battery.

**Solution:**

To find the total current supplied by the battery, we use the formula for power \( P = V \times I \), where \( P \) is power, \( V \) is voltage, and \( I \) is current. Rearranging gives \( I = \frac{P}{V} \).

- For L1: \( I(L1) = \frac{600 \, \text{W}}{120 \, \text{V}} = 5 \, \text{A} \)
- For L2: \( I(L2) = \frac{1200 \, \text{W}}{120 \, \text{V}} = 10 \, \text{A} \)
- For L3: \( I(L3) = \frac{300 \, \text{W}}{120 \, \text{V}} = 2.5 \, \text{A} \)

**Total Current**:

The total current drawn from the battery is the sum of the currents through each lamp:

\[ I_{\text{total}} = I(L1) + I(L2) + I(L3) = 5 \, \text{A} + 10 \, \text{A} + 2.5 \, \text{A} = 17.5 \, \text{A} \]
Transcribed Image Text:**Parallel Circuit with Three Lamps** In the circuit below, there are three lamps connected in parallel: - **Diagram Description**: The diagram shows a battery with a voltage \( V \), labeled as 120 Volts. Three lamps, labeled as L1, L2, and L3, are connected in parallel to the battery. **Lamp Specifications:** - The voltage of the battery is 120 Volts. - Each lamp has a nominal voltage of 120 volts, but they have different power ratings: - \( P(L1) = 600 \, \text{W} \) - \( P(L2) = 1200 \, \text{W} \) - \( P(L3) = 300 \, \text{W} \) **Task:** Calculate the current drawn from the battery. **Solution:** To find the total current supplied by the battery, we use the formula for power \( P = V \times I \), where \( P \) is power, \( V \) is voltage, and \( I \) is current. Rearranging gives \( I = \frac{P}{V} \). - For L1: \( I(L1) = \frac{600 \, \text{W}}{120 \, \text{V}} = 5 \, \text{A} \) - For L2: \( I(L2) = \frac{1200 \, \text{W}}{120 \, \text{V}} = 10 \, \text{A} \) - For L3: \( I(L3) = \frac{300 \, \text{W}}{120 \, \text{V}} = 2.5 \, \text{A} \) **Total Current**: The total current drawn from the battery is the sum of the currents through each lamp: \[ I_{\text{total}} = I(L1) + I(L2) + I(L3) = 5 \, \text{A} + 10 \, \text{A} + 2.5 \, \text{A} = 17.5 \, \text{A} \]
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