Handwrite, more details ### Problem StatementIn the circuit below, the switch is closed at time \( t = 0 \) after being open for a long time.1. Find \( v(t) \) for \( 0 < t \). What is the RC time constant?At time \( t = 1 \) second, the switch is suddenly opened.2. Find \( v(t) \) at \( t = 1 \) second right before the switch opens. [Hint: a capacitor acts as an open circuit when it’s in its steady state].3. Determine the time it takes the capacitor voltage to decay to \( \frac{1}{3} \) of its initial value.4. Find the instantaneous power dissipated by the circuit for all \( t > 1 \) second, as well as the total energy dissipated for all \( t > 1 \) second.### Circuit DescriptionThe circuit consists of:- A voltage source of 11 V.- A switch that controls the connection.- A 1 kΩ resistor in series.- A parallel combination of a 10 kΩ resistor and a 100 μF capacitor, connecting at the point where \( v(t) \) is measured.### Diagram ExplanationThe circuit diagram shows a simple RC series circuit with the following characteristics:- The voltage source is connected to a 1 kΩ resistor, which then connects to a parallel combination of a 10 kΩ resistor and a 100 μF capacitor.- The 11 V supply voltage feeds directly into these components.- The switch controls the starting point of the circuit action described in the problem.This setup is typical for analyzing transient response in RC circuits and involves solving for voltages and dissipated power over time.

In the circuit below, the switch is closed at time t = 0 after being open for a long time. 1. Find v(t) for 0 < t. What is the RC time constant? At time t = 1 second, the switch is suddenly opened. 2. Find v(t) at t = 1 second right before the switch opens. [hint: a capacitor acts as an open circuit when it's in its steady state]. 3. Determine the time it takes the capacitor voltage to decay to 1/3 of its initial value.

In the circuit below, the switch is closed at time t = 0 after being open for a long time. 1. Find v(t) for 0 < t. What is the RC time constant? At time t = 1 second, the switch is suddenly opened. 2. Find v(t) at t = 1 second right before the switch opens. [hint: a capacitor acts as an open circuit when it's in its steady state]. 3. Determine the time it takes the capacitor voltage to decay to 1/3 of its initial value.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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