In the circuit below the currents are named IA la, and lc The current direction isdetermined by the source (out of positive terminal) in the midle and right branches andis clockwise in the left branch.VAB• Ia flows in the left branch of the circuit• le flows in the middle branch of the circuit• Ic flows in the right branch of the circuitAR2R3When applying KVL:R4• transverse the loop in a Clockwise direction• voltage drops are negative.R1VcVblabel the voltage across the resistorswith the same numeric subscript as the resistorR1:= 1.2k2R2= 1.8k2R3:= 1.5kNR4= 0.5k2V= 10VV= 6Va. Redraw the circuit showing current directions and polarities of the voltage acrossthe resistors.b. Write the KVL equations and apply ohms law for theloop R1-R2-R4-Vb (left Loop)loop R3-Vc-Vb-R4 (right Loop)Equation 1Equation 2c. Write the equation for KVL at node "N" Equation 3d. Put the equations in the form below and solve. if a variable does not appear in anequation, let that N =0N1A IA + N18 IB + Nc Ic = k1N24 la + N2B Ig + N2c ·Ic = k2N34 · IA+ N3B Ig + N3c Ic = k3e. Write the KVL equation for the top loop and solve for VAB

KVL - It is applied in a closed loop or mesh .The sum of all voltages in a loop is equal to the sum…

In the circuit below the currents are named Ia la, and le The current direction is determined by the source (out of positive terminal) in the middle and right branches and is clockwise in the left branch. • la flows in the left branch of the circuit • le flows in the middle branch of the circuit • l flows in the right branch of the circuit R2 R3 When applying KVL: • transverse the loop in a Clockwise direction • voltage drops are negative. R4 R1 Ve Vb label the voltage across the resistors with the same numeric subscript as the resistor R1:= 1.2k2 Rx= 1.8k2 1.5k2 R4= 0.5kN V= 10V Ve= 6V a. Redraw the circuit showing current directions and polarities of the voltage across the resistors. b. Write the KVL equations and apply ohms law for the loop R1-R2-R4-Vb (left Loop) loop R3-Vc-Vb-R4 (right Loop) Equation 1 Equation 2 c. Write the equation for KVL at node "N" Equation 3 d. Put the equations in the form below and solve. if a variable does not appear in an equation, let that N=0 N1A LA+ N18 Is + Nac Ic = k1 N24 I4 + N2B I3 + N2c lc = k2 N34 la + N35 Ig + N3c lc = k3 e. Write the KVL equation for the top loop and solve for VAB

In the circuit below the currents are named Ia la, and le The current direction is determined by the source (out of positive terminal) in the middle and right branches and is clockwise in the left branch. • la flows in the left branch of the circuit • le flows in the middle branch of the circuit • l flows in the right branch of the circuit R2 R3 When applying KVL: • transverse the loop in a Clockwise direction • voltage drops are negative. R4 R1 Ve Vb label the voltage across the resistors with the same numeric subscript as the resistor R1:= 1.2k2 Rx= 1.8k2 1.5k2 R4= 0.5kN V= 10V Ve= 6V a. Redraw the circuit showing current directions and polarities of the voltage across the resistors. b. Write the KVL equations and apply ohms law for the loop R1-R2-R4-Vb (left Loop) loop R3-Vc-Vb-R4 (right Loop) Equation 1 Equation 2 c. Write the equation for KVL at node "N" Equation 3 d. Put the equations in the form below and solve. if a variable does not appear in an equation, let that N=0 N1A LA+ N18 Is + Nac Ic = k1 N24 I4 + N2B I3 + N2c lc = k2 N34 la + N35 Ig + N3c lc = k3 e. Write the KVL equation for the top loop and solve for VAB

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

In the circuit below the currents are named IA la, and lc The current direction is
determined by the source (out of positive terminal) in the midle and right branches and
is clockwise in the left branch.
V
AB
• Ia flows in the left branch of the circuit
• le flows in the middle branch of the circuit
• Ic flows in the right branch of the circuit
A
R2
R3
When applying KVL:
R4
• transverse the loop in a Clockwise direction
• voltage drops are negative.
R1
Vc
Vb
label the voltage across the resistors
with the same numeric subscript as the resistor
R1:= 1.2k2
R2= 1.8k2
R3:= 1.5kN
R4= 0.5k2
V= 10V
V= 6V
a. Redraw the circuit showing current directions and polarities of the voltage across
the resistors.
b. Write the KVL equations and apply ohms law for the
loop R1-R2-R4-Vb (left Loop)
loop R3-Vc-Vb-R4 (right Loop)
Equation 1
Equation 2
c. Write the equation for KVL at node "N" Equation 3
d. Put the equations in the form below and solve. if a variable does not appear in an
equation, let that N =0
N1A IA + N18 IB + Nc Ic = k1
N24 la + N2B Ig + N2c ·Ic = k2
N34 · IA+ N3B Ig + N3c Ic = k3
e. Write the KVL equation for the top loop and solve for VAB

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