In the circle below, segment AB is a diameter. If the length of arc ACB is 67, what is the length of the radius of the circle? C

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter44: Solution Of Equations By The Subtraction, Addition, And Division Principles Of Equality
Section: Chapter Questions
Problem 38A
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In the circle below, segment AB is a diameter. If the length of arc is 6 , what is the length of the radius of the circle?

**Problem**

In the circle below, segment \( AB \) is a diameter. If the length of arc \( ACB \) is \( 6\pi \), what is the length of the radius of the circle?

**Diagram Explanation**

- A circle is shown with a diameter labeled \( AB \).
- Three points are marked on the circumference: \( A \), \( B \), and \( C \).
- The diameter \( AB \) connects two points on the circle, passing through the center.
- An arc is indicated by \( \overset{\frown}{ACB} \), covering part of the circle's circumference from point \( A \) to point \( B \) through point \( C \).
  
**Calculation & Conclusion**

To solve for the radius, we use the relationship between the arc length and the circumference of the circle. The given arc length \( \overset{\frown}{ACB} = 6\pi \), which is the length of a semicircle (half of the circle’s circumference).

Thus, the entire circumference of the circle would be:

\[ 2 \times 6\pi = 12\pi \]

The circumference \( C \) of a circle is also given by the formula:

\[ C = 2\pi r \]

where \( r \) is the radius. Setting the two expressions for the circumference equal gives:

\[ 2\pi r = 12\pi \]

Solving for \( r \):

\[ r = \frac{12\pi}{2\pi} = 6 \]

So, the radius of the circle is \( \boxed{6} \).
Transcribed Image Text:**Problem** In the circle below, segment \( AB \) is a diameter. If the length of arc \( ACB \) is \( 6\pi \), what is the length of the radius of the circle? **Diagram Explanation** - A circle is shown with a diameter labeled \( AB \). - Three points are marked on the circumference: \( A \), \( B \), and \( C \). - The diameter \( AB \) connects two points on the circle, passing through the center. - An arc is indicated by \( \overset{\frown}{ACB} \), covering part of the circle's circumference from point \( A \) to point \( B \) through point \( C \). **Calculation & Conclusion** To solve for the radius, we use the relationship between the arc length and the circumference of the circle. The given arc length \( \overset{\frown}{ACB} = 6\pi \), which is the length of a semicircle (half of the circle’s circumference). Thus, the entire circumference of the circle would be: \[ 2 \times 6\pi = 12\pi \] The circumference \( C \) of a circle is also given by the formula: \[ C = 2\pi r \] where \( r \) is the radius. Setting the two expressions for the circumference equal gives: \[ 2\pi r = 12\pi \] Solving for \( r \): \[ r = \frac{12\pi}{2\pi} = 6 \] So, the radius of the circle is \( \boxed{6} \).
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ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,