In the case where the values of sin 52 ° and sin 72 ° are known in the calculator (note that the given sinus values are given for degrees), for two points formed with them, the linear interpolation approximation function and the value of that function for 66 degrees are given correctly in the following? A 9190104551715 g(x)=-0.03664x +2.89192 ve g(66°) = 0.47366 %3D 8715 B g(x)= 0.46709x+0.36409 ve g(66°)= 0.91355 8715 g1s g190 551-98 87155 %3D g(x)= 0.46709x +0.36409 ve g(66°) = 0.90214 1-98 915 D 819004551-8 (r)=-0.03664x+2.89192 ve g(66°)=0.90214 98 g19010455 1-98, g(x)=-0.03664x+ 2.89192 ve g(66°)=-0.02655 0455 g19010455 0455 04551 %3D

In the case where the values of sin 52 ° and sin 72 ° are known in the calculator (note that the given sinus values are given for degrees), for two points formed with them, the linear interpolation approximation function and the value of that function for 66 degrees are given correctly in the following? A 9190104551715 g(x)=-0.03664x +2.89192 ve g(66°) = 0.47366 %3D 8715 B g(x)= 0.46709x+0.36409 ve g(66°)= 0.91355 8715 g1s g190 551-98 87155 %3D g(x)= 0.46709x +0.36409 ve g(66°) = 0.90214 1-98 915 D 819004551-8 (r)=-0.03664x+2.89192 ve g(66°)=0.90214 98 g19010455 1-98, g(x)=-0.03664x+ 2.89192 ve g(66°)=-0.02655 0455 g19010455 0455 04551 %3D

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Numerical analysis

In the case where the values of sin 52 ° and sin 72 ° are known in the calculator (note that the given
sinus values are given for degrees), for two points formed with them, the linear interpolation
approximation function and the value of that function for 66 degrees are given correctly in the
following?
A
9190104551R715
g(x)=-0.03664x +2.89192 ve g(66°) = 0.47366
87155
В
915
g(x)=0.46709.x + 0.36409 ve
87155
915
G190 551-98
n8715
g(66°) = 0.91355
g(x)= 0.46709x+0.36409 ve g(66°)= 0.90214
1-98,
D
1-98.
g19010455
то
-1-98.
g(x)= -0.03664x+ 2.89192 ve g(66°)=-0.02655
%3D
0455
g19010455
04551
0455

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