In the case of continuous least squares approximation, to find a degree 3 polynomial to approximate a continuous function in the interval [a, b] P3 (x) = ao + a1 x + aza? + aza3 we have to solve a system of equations: S. f(x) dæ S a f(m) da S a? f(x) da Sa f(x) da, то,0 то, то,2 то,3 ao m1,0 m1,1 m1,2 m1,3 a1 m2,0 m2,1 m2,2 m2,3 a2 m3,0 m3,1 m3,2 m3,3 az Suppose that a = 0, b = 1. What is the value of m2,1 = ? %3D O 1/4 7/3 O 2 O 81/4
In the case of continuous least squares approximation, to find a degree 3 polynomial to approximate a continuous function in the interval [a, b] P3 (x) = ao + a1 x + aza? + aza3 we have to solve a system of equations: S. f(x) dæ S a f(m) da S a? f(x) da Sa f(x) da, то,0 то, то,2 то,3 ao m1,0 m1,1 m1,2 m1,3 a1 m2,0 m2,1 m2,2 m2,3 a2 m3,0 m3,1 m3,2 m3,3 az Suppose that a = 0, b = 1. What is the value of m2,1 = ? %3D O 1/4 7/3 O 2 O 81/4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![In the case of continuous least squares approximation, to find a degree 3 polynomial to approximate a
continuous function in the interval [a, b]
P3 (x) = ao + a1 x + aza? + aza3
we have to solve a system of equations:
Sa f(x) dæ
то,0 то,1 то,2 то,3
ao
Sa f(a) dz
x f(x)
m1,0 m1,1 m1,2 m1,3
a1
S a? f(x) dr
Sa f(x) da
m2,0
m2,1 m2,2 m2,3
a2
m3,0 m3,1
m3,2 m3,3
a3
Suppose that a = 0, b = 1. What is the value of m2,1 = ?
%3D
O 1/4
7/3
O 2
O 81/4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0586f61e-1595-4e89-a1af-f612a94cf974%2Ffd680d2c-e79d-4122-bb98-25cd5be8839f%2Fiktjfb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the case of continuous least squares approximation, to find a degree 3 polynomial to approximate a
continuous function in the interval [a, b]
P3 (x) = ao + a1 x + aza? + aza3
we have to solve a system of equations:
Sa f(x) dæ
то,0 то,1 то,2 то,3
ao
Sa f(a) dz
x f(x)
m1,0 m1,1 m1,2 m1,3
a1
S a? f(x) dr
Sa f(x) da
m2,0
m2,1 m2,2 m2,3
a2
m3,0 m3,1
m3,2 m3,3
a3
Suppose that a = 0, b = 1. What is the value of m2,1 = ?
%3D
O 1/4
7/3
O 2
O 81/4
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