In the boxes below each structure, provide the appropriate labels: acid, conjugate acid (CA), base, conjugate base (CB). Using pKa values (table given) determine which side the equilibrium will favor, or if it will not favor either side write “neither”. CH3OH2 +Br ------> CH3OH + HBr The image illustrates a chemical equilibrium reaction involving methanol and bromide ion. Here's the transcription and explanation of the diagram:**Chemical Reaction:**1. **Reactants:** - $ \text{CH}_3\text{OH}_2^+ $ (Protonated methanol) - $ \text{Br}^- $ (Bromide ion)2. **Reaction Arrow:** - A bidirectional arrow indicates equilibrium, showing that the reaction can proceed in both forward and reverse directions.3. **Products:** - $ \text{CH}_3\text{OH} $ (Methanol) - $\text{HBr} $ (Hydrobromic acid)**Explanation:**This reaction showcases an acid-base interaction where the protonated form of methanol reacts with a bromide ion to form methanol and hydrobromic acid. The equilibrium suggests a dynamic balance between the reactants and products. Each species is separated by rectangular placeholders, likely indicating areas for further annotation or labeling, perhaps for educational purposes to highlight reaction conditions or additional information.

Conjugate acid-base pair: The acid-base pair which differ by one ionizable hydrogen is called conjugate acid-base pair. If HA is an acid its conjugate base is A- i.e. The conjugate acid/base pair is HA/A- pKa: The negative base 10 logarithm of acid dissociation constant(Ka) is called pKa. The mathematical expression of pKa is, pKa = -log10 Ka Lower the pKa value, stronger the acidic strength. The tendency of a proton donation capacity of an acid is called acid strength. The reaction is given as Equilibrium reaction: CH3OH2++ Br-⇔CH3OH + HBrpKa ; -2.5 6.6 15.5 -9.0 In the above equilibrium reaction, HBr has the lowest pKa value(-9.0), hence HBr is the strongest acid among the species of the reaction. Therefore, HBr readily loses its proton to CH3OH and favors the equilibrium towards to the reactants. Conclusion: The equilibrium favors the left side or towards the reactants.

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In the boxes below each structure, provide the appropriate labels: acid, conjugate acid (CA), base, conjugate base (CB). Using pKa values (table given) determine which side the equilibrium will favor, or if it will not favor either side write “neither”. CH3OH2 +Br ------> CH3OH + HBr

In the boxes below each structure, provide the appropriate labels: acid, conjugate acid (CA), base, conjugate base (CB). Using pKa values (table given) determine which side the equilibrium will favor, or if it will not favor either side write “neither”. CH3OH2 +Br ------> CH3OH + HBr

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter15: Radical Reactions

Section: Chapter Questions

Problem 17CTQ

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Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Question

In the boxes below each structure, provide the appropriate labels: acid, conjugate acid (CA),
base, conjugate base (CB). Using pKa values (table given) determine which side the equilibrium will
favor, or if it will not favor either side write “neither”.
CH3OH2 +Br ------> CH3OH + HBr

The image illustrates a chemical equilibrium reaction involving methanol and bromide ion. Here's the transcription and explanation of the diagram:

**Chemical Reaction:**

1. **Reactants:**
- $ \text{CH}_3\text{OH}_2^+ $ (Protonated methanol)
- $ \text{Br}^- $ (Bromide ion)

2. **Reaction Arrow:**
- A bidirectional arrow indicates equilibrium, showing that the reaction can proceed in both forward and reverse directions.

3. **Products:**
- $ \text{CH}_3\text{OH} $ (Methanol)
- $\text{HBr} $ (Hydrobromic acid)

**Explanation:**
This reaction showcases an acid-base interaction where the protonated form of methanol reacts with a bromide ion to form methanol and hydrobromic acid. The equilibrium suggests a dynamic balance between the reactants and products. Each species is separated by rectangular placeholders, likely indicating areas for further annotation or labeling, perhaps for educational purposes to highlight reaction conditions or additional information.

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