**Bohr Model of the Hydrogen Atom Analysis**In this exercise, we explore the Bohr model of the hydrogen atom, where an electron moves in a circular path around a proton. Given that the speed of the electron is approximately \(2.17 \times 10^6 \, \text{m/s}\), we are tasked with calculating certain properties related to the motion of the electron.**(a) Force Acting on the Electron**- **Objective**: Find the force acting on the electron as it revolves in a circular orbit.- **Details**: - **Radius of Orbit**: \(0.525 \times 10^{-10} \, \text{m}\). - **Magnitude Calculated**: \(8.162 \times 10^{-8} \, \text{N}\). - **Feedback**: This answer was marked incorrect, and additional information is needed for grading.**(b) Centripetal Acceleration of the Electron**- **Objective**: Calculate the centripetal acceleration of the electron.- **Details**: - **Magnitude Calculated**: \(8.96 \times 10^{22} \, \text{m/s}^2\). - **Direction**: Inward. - **Feedback**: This answer was also marked incorrect, requiring further information for grading.**Need Help?**- A support option labeled "Read It" is available for further guidance.**Submission Options**- Users can submit their answers or revert to their last response.(Note: The above responses highlight acknowledgment of the incorrectness of the calculated answers, indicating a need for revising the computations based on the given data and physics principles.)

Answered: Image /qna-images/answer/29560f61-3e57-4293-b060-c091a0d87a5c.jpgBoth Centripetal Force and acceleration acts towards the centre

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In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.17 x 10° m/s. (a) Find the force acting on the electron as it revolves in a circular orbit of radius 0.525 x 10 10 m. magnitude B.162 x 10-8 X Your answer cannot be understood or graded. More Information N direction Enter a number. (b) Find the centripetal acceleration of the electron. 8 96 x 10^22 magnitude X Your answer cannot be understood or graded. More Information m/s2 direction inward Need Help? Read It

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.17 x 10° m/s. (a) Find the force acting on the electron as it revolves in a circular orbit of radius 0.525 x 10 10 m. magnitude B.162 x 10-8 X Your answer cannot be understood or graded. More Information N direction Enter a number. (b) Find the centripetal acceleration of the electron. 8 96 x 10^22 magnitude X Your answer cannot be understood or graded. More Information m/s2 direction inward Need Help? Read It

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

**Bohr Model of the Hydrogen Atom Analysis**

In this exercise, we explore the Bohr model of the hydrogen atom, where an electron moves in a circular path around a proton. Given that the speed of the electron is approximately \(2.17 \times 10^6 \, \text{m/s}\), we are tasked with calculating certain properties related to the motion of the electron.

**(a) Force Acting on the Electron**

- **Objective**: Find the force acting on the electron as it revolves in a circular orbit.
- **Details**:
- **Radius of Orbit**: \(0.525 \times 10^{-10} \, \text{m}\).
- **Magnitude Calculated**: \(8.162 \times 10^{-8} \, \text{N}\).
- **Feedback**: This answer was marked incorrect, and additional information is needed for grading.

**(b) Centripetal Acceleration of the Electron**

- **Objective**: Calculate the centripetal acceleration of the electron.
- **Details**:
- **Magnitude Calculated**: \(8.96 \times 10^{22} \, \text{m/s}^2\).
- **Direction**: Inward.
- **Feedback**: This answer was also marked incorrect, requiring further information for grading.

**Need Help?**
- A support option labeled "Read It" is available for further guidance.

**Submission Options**
- Users can submit their answers or revert to their last response.

(Note: The above responses highlight acknowledgment of the incorrectness of the calculated answers, indicating a need for revising the computations based on the given data and physics principles.)

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