In survey of 7000 women, 4431 says they change their nail polish once a week. Construct a 95% confidence interval for the population proportion of women who changes their nail polish once a week?

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

A:

Q: A survey reveals that 12% of Americans believe Elvis is still alive, with a margin of error of 4…

A: Given: A survey reveals that 12% of Americans believe Elvis is still alive. A margin of error is 4…

Q: According to a recent survey of 1600 people, 62 % feel that the president is doing an acceptable…

A: Obtain the 90% confidence interval for the population proportion of people who feel the president is…

Q: A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a​…

A: The sampled no. of adults, i.e., the sample size, n=1809. The no. of sampled adults who expressed a…

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: The mean hours of worked for United Airlines pilots is 46 hours/month based upon a sample of 25…

A: Given: Sample size, n=25 Sample mean, X=46 hours Sample standard deviation, s=3 hours The level of…

Q: In a survey of 2313 adults, 714 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given, In a survey of 2313 adults, 714 say they believe in UFOs. n=2313 x=714 Sample proportion:…

Q: Find the critical t value to use in making a 98% confidence interval for a mean if the sample size…

A:

Q: Find the critical t value to use in making a 90% confidence interval for a mean if the sample size…

A: Given, confidence level = 90.0 Need to find Critical value t

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: 60 people were asked to measure their pulse rates after completing a 3 km run. The mean was 105…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

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Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: A sample of 400 homeowners includes 124 that expect their home to increase in value in the next…

A: Margin of error: ME=Zα/2 * √p̂(1-p̂)/n

Q: In a survey of 2298 ​adults, 709 say they believe in UFOs. Construct a 95% confidence interval for…

A:

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

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Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: A survey found that 611 out of 663 college graduates cannot correctly spell the word aluminum. Find…

A: Given that  A survey found that 611 out of 663 college graduates cannot correctly spell the word…

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: Suppose that we conduct a survey of 19 millionaires to find out what percent of their income the…

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Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: In a survey of 3246 ​adults, 1418 say they have started paying bills online in the last year.…

A: Given information Number of adults surveyed(n) = 3246 Number of people who started paying bills…

Q: Find the critical t value to use in making an 80% confidence interval for a mean if the sample size…

A:

Q: A survey conducted by the U.S. department of Labor found the 48 out of 500 heads of households were…

A: Given that, n = 500 x = 48 90% confidence interval

Q: A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95%…

A: Obtain the 95% confidence interval for the true proportion of students ready for summer break. The…

Q: The mean reading speed of a random sample of 81 adults is 320 words per minute. Find a 90%…

A: Given: n=81, x=320 and σ=45.   The value of z at 90% confidence level is 1.645. (From the z-table)

Q: In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum…

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Q: Measuring the height of a California redwood tree is very difficult because these trees grow to…

A: 1.The 95% confidence interval estimate of the population slope between the height of the redwood…

Q: study of 30 college students showed that 25 are binge watching series. Find a 95% confidence…

A: given data  n = 30  x = 25 95% ci for p  = ?

Q: A survey of 800 women shoppers found that 17% of them shop on impulse. what is 98% confidence…

A:

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: Wildlife biologists inspect 180 deer taken by hunters and find 36 of them carrying Lyme disease…

A: Since, you have asked multiple question, we will solve the first question for you. If you want any…

Q: In a sample of 190 adults, 133 had children. Construct a 90% confidence interval for the true…

A: Given:n = 190x = 133Confidence level = 90%

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.