In ships' navigation, due north is O degrees, and the heading (i.e. direction) the ship is traveling is the amount of rotation clockwise from due north. Thus, a heading of 20 degrees means traveling at 20 degrees clockwise from due north. A ship leaves port traveling at 10 kn (knots. 1 knot is 1 nautical mile per hour) at a heading of 30 degrees. After two hours, the ship turns to a heading of 100 degrees and travels at 15 kn. The ship stays on this course for three hours. At the end of this time (ie, 5 hours after the ship leaves port), how far is the ship from port, and what is the heading the ship would have to travel at to return to port from this point? Assume the surface of the ocean is perfectly flat.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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In ships' navigation, due north is O degrees, and the heading (i.e. direction) the ship is traveling is the amount of
rotation clockwise from due north. Thus, a heading of 20 degrees means traveling at 20 degrees clockwise from
due north. A ship leaves port traveling at 10 kn (knots. 1 knot is 1 nautical mile per hour) at a heading of 30
degrees. After two hours, the ship turns to a heading of 100 degrees and travels at 15 kn. The ship stays on this
course for three hours. At the end of this time (ie, 5 hours after the ship leaves port), how far is the ship from
port, and what is the heading the ship would have to travel at to return to port from this point? Assume the
surface of the ocean is perfectly flat.
Transcribed Image Text:In ships' navigation, due north is O degrees, and the heading (i.e. direction) the ship is traveling is the amount of rotation clockwise from due north. Thus, a heading of 20 degrees means traveling at 20 degrees clockwise from due north. A ship leaves port traveling at 10 kn (knots. 1 knot is 1 nautical mile per hour) at a heading of 30 degrees. After two hours, the ship turns to a heading of 100 degrees and travels at 15 kn. The ship stays on this course for three hours. At the end of this time (ie, 5 hours after the ship leaves port), how far is the ship from port, and what is the heading the ship would have to travel at to return to port from this point? Assume the surface of the ocean is perfectly flat.
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