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In scenario 2, the elevator is moving with upward acceleration a2 5.51 m/s2. %3D FN.2 N

In scenario 2, the elevator is moving with upward acceleration a2 5.51 m/s2. %3D FN.2 N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In scenario 2, the elevator is moving with upward acceleration a2 = 5.51 m/s?. FN,2 %3D Scenario 2 In scenario 3, the cable breaks and the elevator acceleratés downward at az = g = 9.81 m/s². FN.3 =
Transcribed Image Text:In scenario 2, the elevator is moving with upward acceleration a2 = 5.51 m/s?. FN,2 %3D Scenario 2 In scenario 3, the cable breaks and the elevator acceleratés downward at az = g = 9.81 m/s². FN.3 =
gnment Score: 0% Resources O Hint Check Answer stion 4 of 9 A simple elevator ride can teach you quite a bit about the normal force. There are three different scenarios given detailing the rider's experience in an unnamed hotel. For each scenario, calculate the normal force FN,1-3 acting on the rider if his mass is m = 78.1 kg and the acceleration due to gravity g = 9.81 m/s? In scenario 1, the elevator has constant velocity. FN.1 = N Constant velocity Scenario 1 In scenario 2, the elevator is moving with upward acceleration a2 = 5.51 m/s?. FN.2 =
Transcribed Image Text:gnment Score: 0% Resources O Hint Check Answer stion 4 of 9 A simple elevator ride can teach you quite a bit about the normal force. There are three different scenarios given detailing the rider's experience in an unnamed hotel. For each scenario, calculate the normal force FN,1-3 acting on the rider if his mass is m = 78.1 kg and the acceleration due to gravity g = 9.81 m/s? In scenario 1, the elevator has constant velocity. FN.1 = N Constant velocity Scenario 1 In scenario 2, the elevator is moving with upward acceleration a2 = 5.51 m/s?. FN.2 =
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