In Sample Prob. 8.06, if we only change the coefficient of kinetic friction along the ground-level track to be 0.600. Through what distance L does the glider slide along the track until it stops?

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In Sample Prob. 8.06, if we only change the
coefficient of kinetic friction along the
ground-level track to be 0.600. Through what
distance L does the glider slide along the
track until it stops?
а.
69.3 m
b. 34.6 m
С.
92.3 m
d. 120.4 m
Transcribed Image Text:In Sample Prob. 8.06, if we only change the coefficient of kinetic friction along the ground-level track to be 0.600. Through what distance L does the glider slide along the track until it stops? а. 69.3 m b. 34.6 m С. 92.3 m d. 120.4 m
Figure 8-17 shows a water-slide ride in which a glider is shot
by a spring along a water-drenched (frictionless) track that
takes the glider from a horizontal section down to ground
level. As the glider then moves along the ground-level track,
it is gradually brought to rest by friction. The total mass of
the glider and its rider is m 200 kg, the initial compression
of the spring is d= 5.00 m, the spring constant is k= 3.20 ×
10 N/m, the initial height is h= 35.0 m, and the coefficient
of kinetic friction along the ground-level track is u = 0.800.
Through what distance L does the glider slide along the
ground-level track until it stops?
on the glider to get it moving, a spring force does work on
it, transferring energy from the elastic potential energy of
the compressed spring to kinetic energy of the glider. The
spring force also pushes against a rigid wall. Because there
is friction between the glider and the ground-level track.
the sliding of the glider along that track section increases
their thermal energies.
System: Let's take the system to contain all the interact-
ing bodies: glider, track, spring, Earth, and wall. Then, be-
cause all the force interactions are within the system, the
system is isolated and thus its total energy cannot change.
So, the equation we should use is not that of some external
force doing work on the system. Rather, it is a conservation
of energy. We write this in the form of Eq. 8-37:
KEY IDEAS
Before we touch a calculator and start plugging numbers
into equations, we need to examine all the forces and then
determine what our system should be. Only then can we
decide what equation to write. Do we have an isolated sys-
tem (our equation would be for the conservation of en-
ergy) or a system on which an external force does work
(our equation would relate that work to the system's
change in energy)?
Forces: The normal force on the glider from the track
does no work on the glider because the direction of this
force is always perpendicular to the direction of the
glider's displacement. The gravitational force does work
on the glider, and because the force is conservative we can
associate a potential energy with it. As the spring pushes
(8-42)
This is like a money equation: The final money is equal to
the initial money minus the amount stolen away by a thief.
Here, the final mechanical energy is equal to the initial me-
chanical energy minus the amount stolen away by friction.
None has magically appeared or disappeared.
Calculations: Now that we have an equation, let's find
distance L. Let subscript 1 correspond to the initial state
of the glider (when it is still on the compressed spring)
and subscript 2 correspond to the final state of the glider
(when it has come to rest on the ground-level track). For
both states, the mechanical energy of the system is the
sum of any potential energy and any kinetic energy.
We have two types of potential energy: the elastic po-
tential energy (U, = kx') associated with the compressed
spring and the gravitational potential energy (U, = mgy) as-
sociated with the glider's elevation. For the latter, let's take
ground level as the reference level. That means that the
glider is initially at height y = h and finally at height y = ().
In the initial state, with the glider stationary and ele-
vated and the spring compressed, the energy is
0 = 71
Pn +n + Iy = a
+ mgh.
-0+kd
Figure 8-17 A spring-loaded amusement park water slide.
(8-43)
Transcribed Image Text:Figure 8-17 shows a water-slide ride in which a glider is shot by a spring along a water-drenched (frictionless) track that takes the glider from a horizontal section down to ground level. As the glider then moves along the ground-level track, it is gradually brought to rest by friction. The total mass of the glider and its rider is m 200 kg, the initial compression of the spring is d= 5.00 m, the spring constant is k= 3.20 × 10 N/m, the initial height is h= 35.0 m, and the coefficient of kinetic friction along the ground-level track is u = 0.800. Through what distance L does the glider slide along the ground-level track until it stops? on the glider to get it moving, a spring force does work on it, transferring energy from the elastic potential energy of the compressed spring to kinetic energy of the glider. The spring force also pushes against a rigid wall. Because there is friction between the glider and the ground-level track. the sliding of the glider along that track section increases their thermal energies. System: Let's take the system to contain all the interact- ing bodies: glider, track, spring, Earth, and wall. Then, be- cause all the force interactions are within the system, the system is isolated and thus its total energy cannot change. So, the equation we should use is not that of some external force doing work on the system. Rather, it is a conservation of energy. We write this in the form of Eq. 8-37: KEY IDEAS Before we touch a calculator and start plugging numbers into equations, we need to examine all the forces and then determine what our system should be. Only then can we decide what equation to write. Do we have an isolated sys- tem (our equation would be for the conservation of en- ergy) or a system on which an external force does work (our equation would relate that work to the system's change in energy)? Forces: The normal force on the glider from the track does no work on the glider because the direction of this force is always perpendicular to the direction of the glider's displacement. The gravitational force does work on the glider, and because the force is conservative we can associate a potential energy with it. As the spring pushes (8-42) This is like a money equation: The final money is equal to the initial money minus the amount stolen away by a thief. Here, the final mechanical energy is equal to the initial me- chanical energy minus the amount stolen away by friction. None has magically appeared or disappeared. Calculations: Now that we have an equation, let's find distance L. Let subscript 1 correspond to the initial state of the glider (when it is still on the compressed spring) and subscript 2 correspond to the final state of the glider (when it has come to rest on the ground-level track). For both states, the mechanical energy of the system is the sum of any potential energy and any kinetic energy. We have two types of potential energy: the elastic po- tential energy (U, = kx') associated with the compressed spring and the gravitational potential energy (U, = mgy) as- sociated with the glider's elevation. For the latter, let's take ground level as the reference level. That means that the glider is initially at height y = h and finally at height y = (). In the initial state, with the glider stationary and ele- vated and the spring compressed, the energy is 0 = 71 Pn +n + Iy = a + mgh. -0+kd Figure 8-17 A spring-loaded amusement park water slide. (8-43)
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