) In sage, reducing an integer a modulo m is achieved with the expression a % m. The following sage code implements the fast power algorithm, but a few blanks are missing Fill in the blanks. def fast_power (a, k, m) : """for non-negative integers k, computes a^k modulo m""" if (k 0): == return if ((k % 2) == 1): # k is odd # recursively compute y = a^{k-1} (mod m) y = fast_power (a, k-1, m) return % m else: # k is even # recursively compute y y = fast_power(a, k/2, m) a^{k/2} (mod m) return % m

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Plzz do fast
In sage, reducing an integer a modulo m is achieved with the expression a % m. The
following sage code implements the fast power algorithm, but a few blanks are missing.
Fill in the blanks.
def fast_power (a, k, m):
"""for non-negative integers k, computes a^k modulo m"""
if (k
0):
==
return
--
if ((k % 2)
# k is odd
1) :
==
# recursively compute y = a^{k-1} (mod m)
y = fast_power (a, k-1, m)
return
% m
else:
# k is even
# recursively compute y = a^{k/2} (mod m)
y = fast_power(a, k/2, m)
return
% m
--
Transcribed Image Text:In sage, reducing an integer a modulo m is achieved with the expression a % m. The following sage code implements the fast power algorithm, but a few blanks are missing. Fill in the blanks. def fast_power (a, k, m): """for non-negative integers k, computes a^k modulo m""" if (k 0): == return -- if ((k % 2) # k is odd 1) : == # recursively compute y = a^{k-1} (mod m) y = fast_power (a, k-1, m) return % m else: # k is even # recursively compute y = a^{k/2} (mod m) y = fast_power(a, k/2, m) return % m --
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